$100\ {cm}^{3}$ of $1M$ ${ CH }{ 3 }COOH$ was mixed with $100\ {cm}^{3}$ of $2M$ ${CH}{3}OH$ to form an ester. The change in the initial rate if each solution is diluted with equal volume of water would be:

The rate of this esterification reaction depends on the product of the molar concentrations of the reactants. Diluting both solutions with an equal volume of water halves the concentration of each reactant, changing the rate to one half times one half of the original. This makes the new initial rate 0.25 times the original rate.

• Thanks
• Wrong explanation