Multiple choice

An amount of water of mass $20\ g$, at $0^{0}C$ is mixed with $40\ g$ of water at $100^{0}C$. Final temperature of mixture is:

  1. $-20^{0}C$
  2. $66.67^{0}C$
  3. $5^{0}C$
  4. $0^{0}C$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Using the principle of calorimetry, heat lost by hot water = heat gained by cold water. 40 * 1 * (100 - T) = 20 * 1 * (T - 0). 4000 - 40T = 20T. 60T = 4000. T = 4000/60 = 66.67 degrees Celsius.

AI explanation

Using the principle of calorimetry, heat lost by the hot water equals heat gained by the cold water, giving the formula m1(100 - T) = m2(T - 0). Substitute the masses to get 40(100 - T) = 20T. Solving this gives 4000 - 40T = 20T, so 60T = 4000 and the final temperature is 66.67 degrees C.

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