The ratio of milk and water in $60$ Litres of adulterated milk is $2 : 1$. If the ratio of milk and water is to be $1 : 2$, then the amount of water to be added further is

In the initial 60 L of adulterated milk, the milk to water ratio of 2 to 1 means there are 40 L of milk and 20 L of water. To obtain a new milk to water ratio of 1 to 2 while keeping the milk amount constant at 40 L, the new water amount must be 80 L. Therefore, the amount of water to be added is 80 - 20 = 60 Litres.

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