Multiple choice

The rate of diffusion of $2$ gases '$A$' and '$B$' are in the ratio $16:3$. If the ratio of their masses present in the mixture is $2:3$. Then:

  1. the ratio of their molar masses is $16:1$
  2. the ratio of their molar masses is $1:4$
  3. the ratio of their molar present inside the container is $1:24$
  4. the ratio of their moles present inside the container is $8:3$
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B Correct answer
AI explanation

According to Graham's law of diffusion, the ratio of the rates of diffusion is inversely proportional to the square root of their molar masses, meaning 16/3 equals the square root of (M_B divided by M_A). The ratio of the masses is 2/3, and since moles equals mass divided by molar mass, the ratio of their moles is (2/M_A) divided by (3/M_B). Simplifying this expression using the proportion of the molar masses from Graham's law gives the ratio of their molar masses as 1 to 4.

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