Multiple choice

A man climbs up and a monkey climbs down a rope hanging from a tree with same uniform acceleration separately. If the respective masses of monkey and man are in the ratio 3 : 2, the common acceleration must be

  1. 7/g

  2. 5g

  3. g/9

  4. g/5

  5. g/11
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let T be the tension of a rope. When man climbs up with acceleration a, ... T - m1g = m1a …(1) When a monkey climbs down with same acceleration a ... m2g - T = m2a ….(2) Adding (i) and (ii), we get (m2 - m1)g = (m1 + m2)a Or (1 - m1 / m2)g = (m1 / m2 + 1)a Or (1 - 2 / 3)g = (2 / 3 + 1)a Or (1 / 3)g = (5 / 3)a Or, a = g / 5. Clearly, it is not equal to 5g, hence it is a wrong option.

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