Multiple choice

Boiling water at $100^{0}C$ and cold water at $t^{0}C$ are mixed in the ratio $1:3$ and the resultant maximum temperature was $27^0$C. Assuming no heat losses, the value of t is :

  1. $4^{0}C$
  2. $9.33^{0}C$
  3. $2.67^{0}C$
  4. $6.67^{0}C$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Heat lost = Heat gained. m1 * c * (100 - 27) = m2 * c * (27 - t). Ratio m1:m2 = 1:3. 1 * 73 = 3 * (27 - t). 73 = 81 - 3t. 3t = 8. t = 8/3 = 2.67 degrees Celsius.

AI explanation

Applying the principle of heat exchange, the heat lost by the boiling water equals the heat gained by the cold water, leading to the weighted average formula: 1 multiplied by 100 plus 3 multiplied by t equals 4 multiplied by 27. Simplifying the right side gives 108, so subtracting 100 from 108 leaves 8. Dividing this remainder by 3 gives a value of t equal to 2.67 degrees Celsius.