Tag: vedic methods of multiplication

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Multiple choice multiplication and division vedic methods of multiplication vedic mathematics history of mathematics maths

Find the representation of the rightmost two digits in the cubage of $96$ by Nikhilam formula of Vedic Mathematics.

  1. $100-64$
  2. $-64$
  3. $64$

  4. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

In the Nikhilam cube calculation for 96, the last part is the cube of the deviation (-4)^3 = -64. To make this positive, we borrow from the previous column, resulting in 100 - 64.

Multiple choice multiplication and division vedic methods of multiplication vedic mathematics history of mathematics maths

Perform division of $422\div 11$ using Nikhilam Sutra Method on base $10$. Also, find the quotient$(Q)$ and remainder$(R)$.

  1. $Q=40$ and $R=3$
  2. $Q=39$ and $R=5$
  3. $Q=33$ and $R=3$
  4. $Q=38$ and $R=4$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

For 422/11, base 10, divisor 11 has a deviation of 1. Using Nikhilam division, 422 / 11 = 38 with remainder 4.

Multiple choice multiplication and division vedic methods of multiplication vedic mathematics history of mathematics maths

Which of the following statements is CORRECT?

  1. The product of $\dfrac{231}{119}$ and $\dfrac{117}{118}$ is greater than $\dfrac{231}{119}$
  2. The product of $\dfrac{17}{25}$ and $\dfrac{117}{225}$ is greater than $\dfrac{17}{25}$
  3. The product of $\dfrac{1735}{2001}$ and $\dfrac{2734}{2724}$ is greater than $\dfrac{1735}{2001}$
  4. $\dfrac{1}{3}$ of $\dfrac{4}{5}$ is greater than $\dfrac{3}{4}$ of $\dfrac{8}{7}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Option $[A]$  :  $\dfrac{117}{118}<1$.  
The product of any number with a number less than $1$ is less than that number.
So,  $\dfrac{231}{119}\times\dfrac{117}{118}<\dfrac{231}{119}$.

$\Rightarrow[A]$ is not correct.

Option $[B]$  :  $\dfrac{117}{225}<1$
The product of any number with a number less than $1$ is less than that number.
So,  $\dfrac{17}{25}\times\dfrac{117}{225}<\dfrac{17}{25}$.
$\Rightarrow[B]$ is not correct.

Option $[C]$  :  $\dfrac{2734}{2724}>1$
The product of any number with a number greater than $1$ is greater than that number.
So,  $\dfrac{1735}{2001}\times\dfrac{2734}{2724}>\dfrac{1735}{2001}$.
$\Rightarrow[C]$ is correct.

Option $[D]$  :
$\dfrac{1}{3}\times\dfrac{4}{5}=\dfrac{4}{15}\approx0.267$   and   $\dfrac{3}{4}\times\dfrac{8}{7}=\dfrac{6}{7}\approx0.857$.
But  $0.857>>0.267$.
So, $[D]$ is not correct.


$\therefore$  The correct answer is  $[C]$.