Tag: history of mathematics

Quizzes (6) Questions (199)

Questions Related to history of mathematics

Multiple choice vedic methods of multiplication history of mathematics maths

A jar can hold $4250\,ml$ honey. How much $litre$ honey will be needed to fill $4$ jars?

  1. $16$
  2. $15$
  3. $17$
  4. $17000$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
A jar can hold$=4000+250$
$=4250㎖$ honey
Total honey needed to fill
$4$ jars$=4250\times 4$
$=17000㎖$
$=17ℓ$ is the correct answer.
Multiple choice vedic methods of multiplication history of mathematics maths

Monika takes $\displaystyle{\dfrac{1}{6}}$ hour to walk to the playground and $\displaystyle{\dfrac{1}{3}}$ hour to walk from the playground to school. How much time does it take her to walk to the playground and then to school ? 

  1. $\displaystyle{\dfrac{2}{9}}$ hour
  2. $\displaystyle{\dfrac{1}{3}}$ hour
  3. $\displaystyle{\dfrac{1}{2}}$ hour
  4. $\displaystyle{\dfrac{2}{3}}$ hour
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Monika takes $\dfrac{1}{6}$ hour to walk to the playground.

And $\dfrac{1}{3}$ hour to walk from the playground to school.

She will take time to walk to the playground and then to school
$=\dfrac{1}{6}+\dfrac{1}{3}$
$=\dfrac{1+2}{6}$
$=\dfrac{1}{2}$ hour

Hence, this is the answer.

Multiple choice vedic methods of multiplication history of mathematics maths

In Vedic period, squares and circular shaped altars were used for household rituals, while altars whose shapes were combination of rectangles, triangles and trapeziums were used for public worship.

  1. True

  2. False

  3. Ambiguous

  4. Data Insufficient
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

In ancient India, squares and circular altars were used for household rituals.

The geometry of the Vedic period originated with the construction of altars (or vedis) and fireplaces for performing Vedic rites. Square and circular altars were used for household rituals, while altars, whose shapes were combinations of rectangles, triangles and trapeziums, were required for public worship.

Multiple choice vedic methods of multiplication history of mathematics maths

Half of a number is 12. What is $\dfrac{3}{4}$ of the same number ?

  1. 24

  2. 36

  3. 9

  4. 18
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the number be $x$.

 

Since,

$ \dfrac{x}{2}=12 $

$ x=24 $

 

Since,

$ \Rightarrow \dfrac{3}{4}\times 24 $

$ \Rightarrow 18 $

 

Hence, this is the answer.

Multiple choice vedic methods of multiplication history of mathematics maths

Sonia talked on the telephone to two friends. She talked to Shivani for $\displaystyle{\dfrac{1}{4}}$ hour to Geetika for $\displaystyle{\dfrac{1}{3}}$ How much time did Sonia spend on the telephone ?

  1. $\displaystyle{\dfrac{1}{6}}$
  2. $\displaystyle{\dfrac{2}{7}}$
  3. $\displaystyle{\dfrac{5}{12}}$
  4. $\displaystyle{\dfrac{7}{12}}$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Sonia talked to Shivani for $=\dfrac{1}{4}$ hour

Sonia talked to Geetika for $=\dfrac{1}{3}$ hour

She spend time on the telephone will be
$=\dfrac{1}{4}+\dfrac{1}{3}$
$=\dfrac{7}{12}$ hour

Hence, this is the answer.

Multiple choice vedic methods of multiplication history of mathematics maths

Victor can throw a ball 50$\displaystyle{\dfrac{3}{5}}$ feet. Parth can throw the same ball 48$\displaystyle{\dfrac{1}{3}}$ feet. How much farther can Victor throw the ball than Parth ? 

  1. 2$\displaystyle{\dfrac{2}{15}}$ feet
  2. 2$\displaystyle{\dfrac{4}{15}}$ feet
  3. 2$\displaystyle{\dfrac{3}{5}}$ feet
  4. 2$\displaystyle{\dfrac{4}{5}}$ feet
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Victor can throw a ball $=50\dfrac{3}{5}$ feet

Parth can throw the same ball $=48\dfrac{1}{5}$ feet

Difference,
$=50\dfrac{3}{5}-48\dfrac{1}{3}$
$=\dfrac{253}{5}-\dfrac{145}{3}$
$=\dfrac{253}{5}-\dfrac{145}{3}$
$=\dfrac{34}{15}$
$=2\dfrac{4}{15}$ feet

Hence, this is the answer.

Multiple choice vedic methods of multiplication history of mathematics maths

Using vedic mathematics term "Ekadhik", find the value of $135^2$.

  1. $18625$
  2. $18325$
  3. $19425$
  4. $18225$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Using the Ekadhik method for squaring numbers ending in 5: (n5)^2 = n(n+1) concatenated with 25. For 135, n=13, so 13 * 14 = 182, resulting in 18225.

Multiple choice vedic methods of multiplication history of mathematics maths

If $60$% of $\cfrac{3}{5}$ of a number is $36$, then the number is:

  1. $80$
  2. $100$
  3. $75$
  4. $90$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the number be $x$. Then
$60$% of $\cfrac{3}{5}$ of $x=36$
$\Rightarrow$ $\cfrac{60}{100}\times \cfrac{3}{5}\times x=36$
$\Rightarrow$ $x=(36\times \cfrac{25}{9})=100$
$\therefore$ Required number $=100$