Tag: vedic methods of multiplication

Questions Related to vedic methods of multiplication

Find the cube of $99$ by Nikhilam formula of Vedic Mathematics.

  1. $97299$

  2. $972299$

  3. $973299$

  4. None of these


Correct Option: D

Write multiplication table of $46$ by using Vinculum method and identify fourth term in the table.

  1. $184$

  2. $230$

  3. $143$

  4. $138$


Correct Option: A

If $31z5$ is a multiple of $9$, where $z$ is a digit, what is the value of $z$?

  1. 0

  2. 4

  3. 7

  4. 9


Correct Option: A,D
Explanation:

Given that $31z5$ is a multiple of $9$. 

According to the divisibility rule of $9$, the sum of all the digits should be a multiple of $9$. 
Therefore, 
$3 + 1 + z + 5 = 9\ OR\ 18$
$\Rightarrow z = 9 - 9 = 0$
$\Rightarrow z = 18 - 9 = 9$

Multiply $54, 57$ using NIkhilam formula (sub-base) of vedic mathematics.

  1. $3278$

  2. $3768$

  3. $3078$

  4. None of these


Correct Option: C

Multiply $63, 58$ using NIkhilam formula (sub-base) of vedic mathematics.

  1. $3454$

  2. $3654$

  3. $3754$

  4. None of these


Correct Option: B

Multiply $524$ by $11 $ using vedic mathematics.

  1. $5854$

  2. $5354$

  3. $5774$

  4. None of these


Correct Option: D
Explanation:
To multiply any number by 11 do the following:

Working from right to left

Write the rightmost digit of the starting number down.

Add each pair of digits and write the results down, (carrying digits where necessary right to left).

Finally write down the left most digit (adding any final carry if necessary).

For  5 2 4

5 (5+2) (2+4) 4

5764

There are no options with this.
So, option D is the correct answer.

Multiply $11, 15$ using NIkhilam formula (sub-base) of vedic mathematics.

  1. $145$

  2. $165$

  3. $185$

  4. None of these


Correct Option: B

Multiply $12, 13, 17$ by Nikhilam formula of vedic maths.

  1. $2662$

  2. $2652$

  3. $2552$

  4. None of these


Correct Option: B

$(102\times 98)-(9.5\times 10.5)=$

  1. 9896.25

  2. 10095.75

  3. 21

  4. 9897.75


Correct Option: A
Explanation:

$(102 \times 98) -(9.5 \times 10.5)=(100 + 2) (100 -2) -[(10 -0.5) (10 + 0.5)]$
$=(100^2-2^2) -(10^2 -0.5^2)$
$=10000 -4 -(100 -0.25)$
$=10000 -104 + 0.25$
$=9896 + 0.25=9896.25$

Identify groups to be made in the multiplication $349, 986$ by Urdhwtirgbhyaam method of vedic mathematics.

  1. $ 3\times 9\ / \ 3\times 8+4 \times 9 \ / \ 3\times 6 \ + 4 \times 8 / \ 4\times 6 \ + 9 \times 8 \ / \ 9\times 6\ $

  2. $ 3\times 9\ / \ 3\times 8+4 \times 9 \ / \ 3\times 6\ +9 \times 9+ 4 \times 8 / \ 4\times 6 \ + 9 \times 8 \ / \ 9\times 6\ $

  3. $ 3\times 9\ / \ 4 \times 9 \ / \ 3\times 6\ +9 \times 9+ 4 \times 8 / \ 4\times 6 \ + 9 \times 8 \ / \ 9\times 6\ $

  4. None of these


Correct Option: B