Tag: vedic methods of multiplication

The deviations from base 100 are -2, -1, and -1. The calculation is (98-1-1) | ((-2*-1) + (-1*-1) + (-1*-2)) | (-2*-1*-1), which is 96 | (2+1+2) | -2 = 96 | 5 | -2 = 964498.

The two rightmost digits in the multiplication 98,97, 99 = 100 - (2 + 3 + 1) = 100 - (2)(3)(1)

Using base 50 (sub-base 5*10), the deviations are +1, +2, +3. The calculation is 5^2 * (51+2+3) | 5*(1*2 + 2*3 + 3*1) | (1*2*3) = 25*56 | 5*11 | 6 = 1400 | 55 | 6 = 140556.

The two rightmost digits in the multiplication 98,97, 99 = 100 - (2 + 3 + 1) = 100 - 6 = 94

99  × 99 = 99 (100 - 1)
= 9900 - 99
= 9801

The correct representation of deviations from the base in the multiplication of 101,102,103 by Nikhilam formula of vedic maths is 01, 02 and 03.

For 12/9 with base 10, the divisor 9 has a complement of 1. The division 12/9 gives quotient 1 and remainder 3.

For 96^3, the base is 100 and deviation is -4. The formula is (n + 2d) | 3d^2 | d^3 = (96 - 8) | 3(16) | (-64) = 88 | 48 | -64. Adjusting the negative remainder: 88 | 47 | (100-64) = 884736.

Total number of voters $= 21,35,680$
Number of polling booth $= 235$
So, number of voters at each polling booth $= 21,35,680 \div 235 = 9088$.

Dhwajanka method calculations: 3987/28 gives Q=142, R=11; 5786/78 gives Q=74, R=14; 7396/82 gives Q=90, R=16.