Tag: maths

Quizzes (518) Questions (9324)

Questions Related to maths

Multiple choice maths numbers and place value many forms of ten thousand standard form of numbers number names, numerals and place values

Simplify $\displaystyle (27)^{\frac{-2}{3}} \div \displaystyle (64)^{\frac{-2}{3}}$ is---

  1. $\displaystyle \frac{9}{16}$

  2. 16
  3. $\displaystyle \frac{16}{9}$

  4. 9
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$\displaystyle \frac{(27)^{-2/3}}{ ( 64)^{-2/3}} = \frac{\displaystyle \frac{1}{9}}{ \displaystyle \frac{14}{16}} = \frac{16}{9}$

Multiple choice maths numbers and place value many forms of ten thousand standard form of numbers number names, numerals and place values

Which of the following statement is false?

  1. $\displaystyle 4\cdot 59\times 10^{-3}=0.00459$
  2. $\displaystyle 7\times 10^{-5}=0.00007$
  3. $\displaystyle 1\cdot 03\times 10^{-3}=1030$
  4. $\displaystyle 8\cdot 8\times 10^{-4}=0.00088$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$\displaystyle 1\cdot 03\times 10^{-3}= 0\cdot 00103$
$\displaystyle \therefore $ The given statement is false

Multiple choice maths numbers and place value many forms of ten thousand standard form of numbers number names, numerals and place values

Which of the following expressions is true?

  1. $2940000=$$\displaystyle 2\cdot 94\times 10^{5}$
  2. $502000=$$\displaystyle 5\cdot 02\times 10^{5}$
  3. $3683000=$$\displaystyle 3\cdot 683\times 10^{5}$
  4. $40404000=$$\displaystyle 4\cdot 0404\times 10^{5}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$\displaystyle 502000= 5\cdot 02\times 10^{5}$

Therefore, option B is correct.

Multiple choice maths numbers and place value many forms of ten thousand standard form of numbers number names, numerals and place values

When $70, 000$ is written as $7.0\times10^n$, what is the value of $n$?

  1. $1$
  2. $2$
  3. $3$
  4. $4$
  5. $5$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Given that $70,000$ is written as $7.0$ $\times $ ${10}^{n}$

From this, we can write
$70,000$ $=$ $7.0$ $\times$ ${10}^{n}$
$\Rightarrow {10}^{n}$ $=$ $\dfrac {70,000}{7}$
$\Rightarrow {10}^{n}$ $=$ $10,000$
$\Rightarrow {10}^{n}$ $=$ ${10}^{4}$
$\Rightarrow n$ $=$ $\log _{10}$ ${10}^{4}$
$\Rightarrow n$ $=$ $4$ $\log _{10}$ $10$
$\Rightarrow $ $=$ $4$
Therefore, the value of $n$ is $'4'$.