Quantitative Aptitude

Problems on Ages

346 Questions

Problems on Ages involve calculating current, past, or future ages using ratios, averages, and simple equations. These questions are a regular feature in the arithmetic section of most competitive exams. Practicing these problems helps improve calculation speed and accuracy for time management during tests.

age ratiosaverage age problemspresent age calculationsfuture age equationsfamily age puzzles

Problems on Ages Questions

Multiple choice geography ideas of development study of population in tamil nadu population and migration human geography in tamil nadu

According to the census of India 2011 the life expectancy of male and female is

  1. 64.6 years for male and 67.7 years for female.

  2. 67.7 years for male and 64.6 years for female.

  3. 68 years for male and 65 years for female.

  4. 65 years for male and 68 years for female.

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

According to the census of India 2011 the life expectancy of male and female is 64.6 years and 67.7 years respectively.

Multiple choice maths direct proportion and inverse proportion inverse proportion rule of three types of proportions

Present ages of $X\;and\;Y$ are in the ratio $5\,\colon\,6$ respectively. Seven years hence this ratio will become $6\,\colon\,7$ respectively. What is $X's$ present age ?

  1. $35$ years
  2. $42$ years
  3. $49$ years
  4. Can't be determined

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

As per question,
$\frac { x }{ y } =\frac { 5 }{ 6 } $
$6x=5y$
$6x-5y=0$  multiply eq by 6.
$36x-30y=0$  ...eq 1
$\frac { x+7 }{ y+7 } =\frac { 6 }{ 7 } $
$7x+49=6y+42$  
$7x-6y=-7$  ...multiply eq by 5.
$35x-30y=-35$.... eq 2
eq1-eq2
$x=35$
Answer (A) 35 Years


Multiple choice physics the universe types of galaxies galaxies constellations

According to best estimates today, how old is the universe ?

  1. between ten and twenty thousand years.

  2. between ten and twenty million years.

  3. between ten and twenty billion years.

  4. between ten and twenty trillion years.

  5. between ten and twenty quadrillion years.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The age of universe is approximately 13.82 billion years. It is the time that has passes since the Big Bang that started the building of matter, time and space itself. Time had no existence before the Big Bang.
Hence correct answer is option C.

Multiple choice geography asia : the largest continent - location and physical features location, political and physical division of asia introduction of the continents - africa and asia asia

The Median age of asia is ___________ years.

  1. 30.7

  2. 35.7

  3. 28.7

  4. 36.7

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
The current population of Asia is 4,586,475,221.
Asia population is equivalent to 59.66% of the total world population.
Asia ranks number 1 among regions of the world (roughly equivalent to "continents"), ordered by population.
The population density in Asia is 148 per Km2 (383 people per mi2).
The total land area is 31,033,131 Km2 (11,981,954 sq. miles)
46.8 % of the population is urban (2,147,483,647 people in 2019)
The median age in Asia is 30.7 years.
Multiple choice biology biology : an introduction introduction to organization of life signs of life what is living?


Life span of Parrot is

  1. 25 yrs

  2. 50 yrs

  3. 140 yrs

  4. 15 yrs

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Each organism has a specific lifespan in which it grows, undergoes a reproductive phase and then dies. Different organisms have a different lifespan.

the approximate lifespan of the parrot is 140-150 years. It has quite a long lifespan then any other birds.

So, the correct option is '140y years'

Multiple choice applications of quadratic equations solving (simple) problems word problems based on quadratic equations quadratic equation maths

Two years ago Sam's age was $\displaystyle 4 \frac{1}{2}$ times the age of his son. Six years ago, his age was twice the square of the age of his son. What is the present age of Sam's son ?

  1. $20$
  2. $10$
  3. $15$
  4. $13$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let $m$ be the age of Sam and $s$ be the age of his son
Then, 2 years ago,
$(m -2) = \dfrac{9}{2} (s-2)$
$2m - 4 = 9s - 18$
$2m = 9s - 14 ...(i)$
$6$ years ago,
$(m - 6) = 2(s- 6)^2$
$\left(\dfrac{9s-14}{2} - 6\right) = 2(s-6)^2$
$9s - 14 - 12 = 4(s^2 - 12s + 36)$
$9s - 26 = 4s^2 - 48s + 144$
$4s^2 - 57s + 170 = 0$
$s = \dfrac{57 \pm \sqrt{529}}{8}$ = $\dfrac{57 \pm 23}{8} = 10, 4.25$
Neglect the 4.25 which is a fraction. 
Hence, age of his son is $10$ years.

Multiple choice applications of quadratic equations solving (simple) problems word problems based on quadratic equations quadratic equation maths

One year ago, the father was $8$ times as old as his son. Now his age is square of the son's age. Find their present ages.

  1. Present age of father is $36$ years and that of his son is $6$ years.
  2. Present age of father is $49$ years and that of his son is $7$ years.
  3. Present age of father is $64$ years and that of his son is $8$ years.
  4. Present age of father is $25$ years and that of his son is $5$ years.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the present age of the son be $x$.
Let the father's present age be $y$.
One year ago, $y-1=8(x-1)$
$\Rightarrow  y-1=8x-8$
$\Rightarrow  y=8x-7$
Now applying the condition, we get
$(8x-7)=x^{2}$
$\Rightarrow x^{2}-8x+7=0$
$\Rightarrow (x-1)(x-7)=0$
$\Rightarrow x=1$ or $x=7$

Hence, the present age of son is either $1$ year or $7$ years.

Multiple choice applications of quadratic equations solving (simple) problems word problems based on quadratic equations quadratic equation maths

Five years hence, father's age will be $3$ times the age of his son. Five years ago, father was seven times as old as his son. The age of the son at present is

  1. $10$ years
  2. $15$ years
  3. $20$ years
  4. $40$ years
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let $5$ years ago, the ages of son and father were $x$ and $7x$ years respectively, then 
$\displaystyle 3\left( x+5+5 \right) =7x+5+5$
$\displaystyle \Rightarrow  3x+30=7x+10$
$\displaystyle \Rightarrow  4x=20$
$\displaystyle \Rightarrow  x=5$
Thus, present age of son $= x + 5 = 10$ years

Multiple choice applications of quadratic equations solving (simple) problems word problems based on quadratic equations quadratic equation maths

The age of a man is the square of his son's age. A year ago, the man's age was $8$ times the age of his son. What is the present age of the man?

  1. $47\ yr$
  2. $49\ yr$
  3. $36\ yr$
  4. $48\ yr$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

let present age of son be $x$

present age of father be ${ x }^{ 2 }$
$1$ year ago
age of son $=x-1$
age of father = ${ x }^{ 2 }$-1
so 
${ x }^{ 2 }-1=8(x-1)$
${ x }^{ 2 }-8x+7=0$
$(x-7)(x-1)=0$
$x=7$
son's age $= 7 years$
man's age = ${ x }^{ 2 }=49$ years

Multiple choice applications of quadratic equations solving (simple) problems word problems based on quadratic equations quadratic equation maths

A girl is twice as old as her sister. Four years hence, the product of their ages (in years) will be 160. Their present ages are 6 years and 12 years.

  1. True

  2. False

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$\Rightarrow$  Let present age of girl be $2x$.

$\Rightarrow$  Then, age of her sister be $x.$
According to the question,
$\Rightarrow$  $(2x+4)(x+4)=160$
$\Rightarrow$  $2x^2+8x+4x+16=160$
$\Rightarrow$  $2x^2+12x+16-160=0$
$\Rightarrow$  $2x^2+12x-144=0$
$\Rightarrow$  $2(x^2+6x-42)=0$
$\Rightarrow$  $x^2+6x-72=0$
$\Rightarrow$  $x^2+12x-6x-72=0$
$\Rightarrow$  $x(x+12)-6(x+12)=0$
$\Rightarrow$  $(x+12)(x-6)=0$
$\Rightarrow$  $x+12=0$ and $x-6=0$
$\therefore$  $x=-12$ and $x=6$
$\Rightarrow$  Age cannot be negative.
$\therefore$  $x=6$
$\Rightarrow$  $2x=2\times 6=12$
$\therefore$  The present ages of girls are $6\,years$ and $12\,years.$

Multiple choice computer and ms office mathematical methods for economics economics

The age of son and father is in the ratio of 3:7, if the age of the father is 42, the age of the son will be___

  1. 21 years

  2. 24 years

  3. 18 years

  4. 20 years

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The ratio of son to father is 3:7. If 7 parts equal 42, then 1 part equals 6. Therefore, the son's age (3 parts) is 3 * 6 = 18.

Multiple choice maths mixture types of ratios ratios in proportion mathematical logic

Present ages of Amit and his father are in the ratio 2:5 respectively. Four years hence the ratio of their ages becomes 5:11 respectively. What was the father's age five years ago?

  1. 40 years

  2. 45 years

  3. 30 years

  4. 35 years

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

 Let the present ages of Amit and his father be 2x and 5x years respectively 
Four years hence 
Amit's Age = ( 2x+ 4) years
Father's age = (5x + 4) years
Given $\displaystyle \frac{2x+4}{5x+4}=\frac{5}{11}\Rightarrow (2x+4)=5(5x+4)$


$\displaystyle \Rightarrow 22x+44=25x+20\Rightarrow 3x=24\Rightarrow x=8$

$\displaystyle \therefore $ Father's present age = ( 5 x 8) years = 40 years Father's age 5 years ago = ( 40 - 5)= 35 years