Quantitative Aptitude

Problems on Ages

346 Questions

Problems on Ages involve calculating current, past, or future ages using ratios, averages, and simple equations. These questions are a regular feature in the arithmetic section of most competitive exams. Practicing these problems helps improve calculation speed and accuracy for time management during tests.

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Problems on Ages Questions

Multiple choice roman numbers and numbers upto hundred roman numerals knowing our numbers maths

Raju is 22 years old and Ramu is 19 years old. Write the diference of their ages in Roman system.

  1. III

  2. XXDI

  3. XXXLII

  4. XXXLL
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Raju is 22 years old and Ramu is 19 years old.

$\text{Difference between Raju age and Ramu age=19-16=3years}$
$\text{In roman three is represented as III}$
Option A is correct.

Multiple choice roman numbers and numbers upto hundred roman numerals knowing our numbers maths

Anita's age is 48 years Express it in Roman system

  1. XXXXVIIII

  2. XLVII

  3. XLVIII

  4. XLV
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The Roman numerals are represented 
by the following letters:

I = 1

V = 5

X = 10

L = 50

C = 100

D = 500

M = 1000

If a numeral is followed by another numeral of lower denomination, the two are added together;

if it is preceded by one of lower denomination, the smaller numeral is subtracted from the greater.


XLVIII = 50-10+5+1+1+1 = 48

Multiple choice roman numbers and numbers upto hundred roman numerals knowing our numbers maths

Raghu is 21 years old and Kavitha is 22 years old Write the sum of their ages in Roman system

  1. XXXIII

  2. XLIII

  3. LIII

  4. XLCIII
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The Roman numerals are represented by the following letters:

I = 1

V = 5

X = 10

L = 50

C = 100

D = 500

M = 1000

If a numeral is followed by another numeral of lower denomination, the two are added together;

if it is preceded by one of lower denomination, the smaller numeral is subtracted from the greater.

 

21 + 22 = 43
43 →→ XLIII

Multiple choice roman numbers and numbers upto hundred roman numerals knowing our numbers maths

Raju is $22$ years old and Ramu is $19$ years old. Write the difference of their ages in Roman system.

  1. III

  2. XXDI

  3. XXXLII

  4. XXXLL
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Raju's age is $22$ years and Ramu's age is $19$ years.

The difference between their ages is $22-19=3$ years
And $3$ can be written in roman value as III.

Multiple choice maths equation reducing simple equations to simpler form solving linear equations solution of a linear equation in one variable

The square roots of Radhas and Krishs ages have a sum of $7$ and a difference of $1$. If Radha is older than Krish, how old is Radha?

  1. $13$
  2. $4$
  3. $9$
  4. $16$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the ages of Radha and krish be $x^{2}$ and $y^{2}$ respectively

Then square roots of their age will be $x$ and $y$ respectively.

Then according to the question,

$x+y=7$ ..(1)

$x-y=1$...(2)

Adding (1) and (2)

$2x=8$

$x=4$

From (1)

$4+y=7$

$y=3$

Therefore $x^{2}=16$ and $y^{2}=9$

As radha is older,hence age of radha is 16years.

Multiple choice maths equation reducing simple equations to simpler form solving linear equations solution of a linear equation in one variable

The present ages of a father and his son are in the ratio $7 : 3$ and the ratio of their ages will be $2 : 1$ after $10 $ years. Then, the present age of father (in years) is -

  1. $42$
  2. $56$
  3. $70$
  4. $77$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the present ages of father and son be $7x$ and $3x$.

After $10$ years, their ages will be $7x+10$ and $3x+10$.
According to the question, we have
$\dfrac {7x+10}{3x+10}=\dfrac {2}{1}$
$1(7x+10)=2(3x+10)$
$7x+10=6x+20$
$7x-6x=20-10$
$x=10$
Then present age of father is $7x$, i.e. $7\times 10=70$ years.

Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

Four years ago, the father's age was three times the age of his son. The total of the age of the father and the son after four years will be $64$ years. What is the father's age at present?

  1. $32$ years
  2. $36$ years
  3. $44$ years
  4. $40$ years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

fathers present age $= x$ years.

sons present age $= y$ years.  

four years ago, fathers age $=3 \times $ sons age.
$(x-4)=(y-4)\times 3$
$x=3y-8$.....(i) 

after 4 years, fathers age$ +$ sons age $= 64 $
$x+4+y+4=64 $
$x+y=56$.....(ii) 

solve for $x$
$x=3\times 56-3x-8$ 
$4x=160$ 
$x=40$ years  

D is correct.   

Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

Two years ago the mean age of $40$ people was $11$ years. Now a person left the group and the mean age is changed to $12$ years, then the age of the person who left the group is?

  1. $52$ years
  2. $48$ years
  3. $54$ years

  4. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Sum of ages 2 years ago = 40*11 = 440. Sum of ages now = 440 + 40*2 = 520. After one person leaves, 39 people have mean age 12, sum = 39*12 = 468. Age of person = 520 - 468 = 52.

Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

Five years ago Anjali's age was twice Sarita's age. Five years hence, their ages will be $4 : 3$. Anjali's present age is 

  1. $15$ years
  2. $10$ years
  3. $12$ years
  4. $16$ years
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let A and S be current ages. (A-5) = 2(S-5) => A-2S = -5. (A+5)/(S+5) = 4/3 => 3A+15 = 4S+20 => 3A-4S = 5. Solving the system: 2A-4S = -10 and 3A-4S = 5. Subtracting gives A = 15.

Multiple choice maths calculations and mental strategies 1 equations from statements forming equations from statements writing mathematical statements

After $12$ years I shall be $3$ times as old as I was $4$ years ago. Find my present age.

  1. $12$
  2. $13$
  3. $14$
  4. $15$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
Let my present age$=x$ years

After $12$ years my age$=x+12$ years

$4$ years ago my age $=x-4$ years

According to the question,

$x+12=3\left(x-4\right)$

$\Rightarrow x+12=3x-12$

$\Rightarrow 3x-x=12+12$

$\Rightarrow 2x=24$ or $x=\dfrac{24}{2}=12$ years.

$\therefore$ my present age is $12$ years.