Quantitative Aptitude

Problems on Ages

346 Questions

Problems on Ages involve calculating current, past, or future ages using ratios, averages, and simple equations. These questions are a regular feature in the arithmetic section of most competitive exams. Practicing these problems helps improve calculation speed and accuracy for time management during tests.

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Problems on Ages Questions

Multiple choice
  1. 17.5

  2. 27.5

  3. 37.5

  4. 19.5

  5. none

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

X + Y = 45 (1) Y + Z = 55 (2)
X + Z = 65 (3) (X + Z) – (X + Y) = 65 – 45 [Equation(2) – (1)] = Z – Y = 20 (4) (Z – Y) + (Z + Y) = 20 + 55 [Equation(4) + (2)] = 2Z = 75 = Z = 37.5 Y + 37.5 = 55 (Substituting the value of Z in equation 2) = Y = 17.5

Multiple choice
  1. 44 years

  2. 32 years

  3. 22 yrs

  4. 45 years

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let son be x years old. Father = 2x 20 years ago, son = x - 20 father = 2x - 20 2x - 20 = 12*(x - 20) 2x - 20 = 12x - 240 Add 20 to both sides. 2x = 12x - 240 + 20 2x = 12x - 220 Add - 12x to both sides. 2x - 12x = 12x - 12x - 220 -12x + 2x = -240 + 20 -10x = -220 Divide by -10. x = -220/-10 x = 22 (son's age) Father's age = 2*22 = 44 years

Multiple choice
  1. 45 year

  2. 60 year

  3. 75 year

  4. 65 year

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

"the man is 3 times as old as his son" ___ f = 3s "15 years ago, the man was 9 times as old as his son was then" ___ f - 15 = 9(s - 15) substituting ___ 3s - 15 = 9(s - 15) distributing ___ 3s - 15 = 9s - 135 adding 135 - 3s ___ 120 = 6s dividing by 6 ___ 20 = s substituting ___ f = 3(20) = 60 Therefore, after 15 years, the age of the man will be = 60 + 15 = 75 years.