Quantitative Aptitude
Problems on Ages
346 Questions
Problems on Ages involve calculating current, past, or future ages using ratios, averages, and simple equations. These questions are a regular feature in the arithmetic section of most competitive exams. Practicing these problems helps improve calculation speed and accuracy for time management during tests.
age ratiosaverage age problemspresent age calculationsfuture age equationsfamily age puzzles
Problems on Ages Questions
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26 years
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20 years
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14 years
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46 years
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None of these
B
Correct answer
Explanation
Let the present age of B be x and of A be (60-x).
(60-x)-6 : x-6 = 5 : 1 or x = 14
B's age after 6 years = 14+6 = 20
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6 years
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3 years
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9 years
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15 years
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None of these
B
Correct answer
Explanation
Let the ages be x-6, x-3, x, x+3, x+6.
Sum of ages = 5x
Also, 5x = 45
So, x = 9 or x-6 = 3
The age of the youngest son is 3 years.
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10 years
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13 years
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5 years
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9 years
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None of these
A
Correct answer
Explanation
Let the age of Z be x, age of Y be 2x and age of X be 2x+3.
Sum of ages = x+2x+2x+3 = 5x+3
5x+3 = 28 or 5x = 25 or x = 5
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50 years
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18 yrs
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17 years
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3 years
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Insufficient data
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16 years
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40 years
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48 years
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24 years
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None of these
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24 years
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22 years
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26 years
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46 years
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None of these
B
Correct answer
Explanation
Let the daughter's present age be x.
Present age of mother = x + 24
x + 26 : x + 2 = 2 : 1 or x = 22
A
Correct answer
Explanation
According to World Health Organization's Health Statistics 2011, 63 years is the life expectancy of a male Indian.
A
Correct answer
Explanation
X + Y = 45 (1)
Y + Z = 55 (2)
X + Z = 65 (3)
(X + Z) – (X + Y) = 65 – 45 [Equation(2) – (1)]
= Z – Y = 20 (4)
(Z – Y) + (Z + Y) = 20 + 55 [Equation(4) + (2)]
= 2Z = 75
= Z = 37.5
Y + 37.5 = 55 (Substituting the value of Z in equation 2)
= Y = 17.5
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44 years
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32 years
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22 yrs
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45 years
A
Correct answer
Explanation
Let son be x years old.
Father = 2x
20 years ago,
son = x - 20
father = 2x - 20
2x - 20 = 12*(x - 20)
2x - 20 = 12x - 240
Add 20 to both sides.
2x = 12x - 240 + 20
2x = 12x - 220
Add - 12x to both sides.
2x - 12x = 12x - 12x - 220
-12x + 2x = -240 + 20
-10x = -220
Divide by -10.
x = -220/-10
x = 22 (son's age)
Father's age = 2*22 = 44 years
D
Correct answer
Explanation
Let the present ages of A and B be 4x and 5x, respectively.
= 4x - 5x = 8
= x = 8
Now, present age of A is (4x) 32 and B is (5x) is 40.
= 40 + 32 = 72.
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45 year
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60 year
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75 year
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65 year
C
Correct answer
Explanation
"the man is 3 times as old as his son" ___ f = 3s
"15 years ago, the man was 9 times as old as his son was then" ___ f - 15 = 9(s - 15)
substituting ___ 3s - 15 = 9(s - 15)
distributing ___ 3s - 15 = 9s - 135
adding 135 - 3s ___ 120 = 6s
dividing by 6 ___ 20 = s
substituting ___ f = 3(20) = 60
Therefore, after 15 years, the age of the man will be = 60 + 15 = 75 years.
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48
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60
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66
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Cannot be determined
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none
B
Correct answer
Explanation
Let the present ages of Jhadhav and Vijay be 3x and 7x, respectively.
= 7x – 3x = 24
= x = 24/4 = 6
Therefore, the present ages of Jhadhav and Vijay are 42 and 18, respectively.
= Sum of their ages = 42 + 18 = 60
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20,35,45
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8,20,28
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16,28,36
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None of these
C
Correct answer
Explanation
Let the three ages be 4x, 7x, and 9x. Eight years ago, their ages were (4x-8), (7x-8), and (9x-8). The sum was (4x-8) + (7x-8) + (9x-8) = 20x - 24 = 56. Solving: 20x = 80, so x = 4. Present ages are 4*4=16, 7*4=28, and 9*4=36.
D
Correct answer
Explanation
Let the present ages of P and Q be 5x and 8x, respectively.
(5x + 4)/(8x + 4) = 2/3
= 3(5x + 4) = 2(8x + 4)
= 15x + 12 = 16x + 8
= x = 4
Therefore, the present age of Q = 8x = 32.