Multiple choice

The present age of three persons are in the proportion of 4:7:9. Eight year ago, the sum of their ages was 56. Find their present ages.

  1. 20,35,45

  2. 8,20,28

  3. 16,28,36

  4. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the three ages be 4x, 7x, and 9x. Eight years ago, their ages were (4x-8), (7x-8), and (9x-8). The sum was (4x-8) + (7x-8) + (9x-8) = 20x - 24 = 56. Solving: 20x = 80, so x = 4. Present ages are 4*4=16, 7*4=28, and 9*4=36.

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