Multiple choice

A father is twice as old as his son. Twenty years ago, the age of the father was 12 times the age of the son. The present age of the father is

  1. 44 years

  2. 32 years

  3. 22 yrs

  4. 45 years
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A Correct answer
Explanation

Let son be x years old. Father = 2x 20 years ago, son = x - 20 father = 2x - 20 2x - 20 = 12*(x - 20) 2x - 20 = 12x - 240 Add 20 to both sides. 2x = 12x - 240 + 20 2x = 12x - 220 Add - 12x to both sides. 2x - 12x = 12x - 12x - 220 -12x + 2x = -240 + 20 -10x = -220 Divide by -10. x = -220/-10 x = 22 (son's age) Father's age = 2*22 = 44 years

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