Multiple choice

A father is twice as old as his son. 20 years back, he was twelve times as old as the son. What are their present ages?

  1. 24,12

  2. 44,22

  3. 48,24

  4. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the son's present age be x. The father's present age is 2x. Twenty years ago, their ages were (2x-20) and (x-20). At that time, the father was 12 times as old: (2x-20) = 12(x-20). Solving: 2x - 20 = 12x - 240, giving 10x = 220, so x = 22. Son is 22 years old, father is 44 years old.

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