Chemistry

Organic Chemistry Fundamentals

287 Questions

Organic chemistry fundamentals cover the structure, properties, and reactions of carbon containing compounds. The questions explore functional groups, isomerism, homologous series, and basic reaction mechanisms. This forms the basis of general chemistry across multiple examination formats.

Functional groupsIsomerism typesHomologous seriesCycloalkanesOrganic monomers

Organic Chemistry Fundamentals Questions

Multiple choice isomerism of amines organic compounds with functional group containing nitrogen

The number of isomeric primary amine possible for the formula $C _3H _9N$ :

  1. 2

  2. 3

  3. 5

  4. 6
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The following primary amines are possible for $C _3H _9N$

(i) $CH _3-CH _2-CH _2-NH _2$    propyl amine
(ii) $CH _3-\underset {|}{CH}-CH _3$                   $2-$aminopropane   (Isopropyl amine)
                  $NH _2$
$\therefore 2$ primary amines are possible.

Multiple choice isomerism of amines organic compounds with functional group containing nitrogen

A racemic mixture contains equal _____ of dextrorotatory and laevorotatory isomers.

  1. No. of molecules

  2. Masses

  3. No. of moles

  4. All the above are correct.
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A racemic mixture contains equal no. of moles or no. of molecules or masses because the only rotation is different, one is having d and another is having l.

Multiple choice isomerism of amines organic compounds with functional group containing nitrogen

How may total structural isomers of $3^o$ amines are possible with the molecular formula $C _6H _{15}N$

  1. 4

  2. 7

  3. 6

  4. 5
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For a tertiary (3 degree) amine with formula C6H15N, the nitrogen is bonded to three alkyl groups. The possible combinations of alkyl groups (summing to 6 carbons) are: (methyl, methyl, butyl) - 2 isomers; (methyl, ethyl, propyl) - 2 isomers; (ethyl, ethyl, ethyl) - 1 isomer; (methyl, isopropyl, ethyl) - 1 isomer; (methyl, propyl, ethyl) - 1 isomer. Total is 7.

Multiple choice isomerism of amines organic compounds with functional group containing nitrogen

In the given example B,C and B,D are :

(a) $CH _3-CH _2-CH _2 - CH _2NH _2$
Butanamine $(1^o)$

(b) $CH _3-CH _2-\overset{NH _2}{\overset{|}{C}H} - CH _3$ 
Butan-2-amine $(1^o)$

(c) $CH _3-\overset{CH _3}{\overset{|}{C}H} - CH _2-NH _2$
2-Methylpropanamine $(1^o)$

(d) $CH _3-\!\!\!\!\underset{\quad CH _3}{\underset{|}{\overset{\quad CH _3}{\overset{|}{C}}}\!\!\!\!-}NH _2$
2-methylpropan-2-amine $(1^o)$

(e) $CH _3-CH _2-CH _2-NH - CH _3$
N-methylpropanamine $(2^o)$

  1. Positional isomers

  2. Chain isomers

  3. Functional isomers

  4. Metamers
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

B,C and B,D are exbhits chain isomerism as the pairs are differed in their longest chain. Hence option B is correct.

Multiple choice isomerism of amines organic compounds with functional group containing nitrogen

Which of the following type/(s) of isomerism is shown in  the amine of the formula $C _4H _{11}N$ :

  1. Chain isomerism

  2. Metamerism

  3. Position isomerism

  4. All of the above.
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The amine of the formula $C _4H _{11}N$ shows chain  isomerism, metamerism, position  isomerism as well as functional group  isomerism.

Multiple choice isomerism of amines organic compounds with functional group containing nitrogen

In the given compound A,C and A,D are exbhits which of the following isomerism :

(a) $CH _3-CH _2-CH _2 - CH _2NH _2$
Butanamine $(1^o)$

(b) $CH _3-CH _2-\overset{NH _2}{\overset{|}{C}H} - CH _3$ 
Butan-2-amine $(1^o)$

(c) $CH _3-\overset{CH _3}{\overset{|}{C}H} - CH _2-NH _2$
2-Methylpropanamine $(1^o)$

(d) $CH _3-!!!!\underset{\quad CH _3}{\underset{|}{\overset{\quad CH _3}{\overset{|}{C}}}!!!!-}NH _2$
2-methylpropan-2-amine $(1^o)$

(e) $CH _3-CH _2-CH _2-NH - CH _3$
N-methylpropanamine $(2^o)$

  1. Chain isomerism

  2. position isomerism

  3. Functional isomerism

  4. Metamerism
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

A,C and A,D are exbhits chain isomerism as the pairs are differed in their longest chain. Hence option A is correct.

Multiple choice chemistry hydroxy compounds and ethers alcohol nomenclature of alcohols and phenols introduction to alcohols

Tertiary alcohol on treatment with cyanide in presence of conc. ${ H } _{ 2 }{ SO } _{ 4 }$ gives corresponding primary amine. This reaction is called as :

  1. Schmidt reaction

  2. Curtius degradation

  3. Leuckart reaction

  4. Ritter reaction
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The reaction of a tertiary alcohol with hydrogen cyanide in the presence of concentrated sulfuric acid to yield a primary amine is known as the Ritter reaction. It involves the formation of a carbocation intermediate followed by the addition of a nitrile.

Multiple choice chemistry introduction to organic chemistry bonding in organic molecule tetravalence of carbon: shapes of organic compounds introduction to carbon and its compounds

In which compound enol form is maximum

  1. $CH _3-\overset{\overset{O}{||}}C-CH _3$
  2. ${ CH } _{ 3 }-CH=O$
  3. ${ CH } _{ 3 }-\underset { || }{ C } -{ CH } _{ 2 }-CH _3\\ \quad \quad \quad O$
  4. ${ CH } _{ 3 }-{ CH _2 } -{ CH } _{ 3 }\\ \quad \quad \quad \quad $
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Enol content is higher in beta-dicarbonyl compounds due to intramolecular hydrogen bonding and resonance stabilization of the enol form. Option C is a beta-diketone.

Multiple choice chemistry materials we use soap and detergents soap soap and detergent

The soap molecule has a :

  1. hydrophilic head and a hydrophobic tail

  2. hydrophobic head and a hydrophilic tail

  3. hydrophobic head and a hydrophobic tail

  4. hydrophilic head and a hydrophilic tail
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
The basic structure of all soaps is essentially the same, consisting of a long hydrophobic (water-fearing) hydrocarbon chain tail and a hydrophilic (water-loving) anionic head.

Hence the correct option is A.
Multiple choice chemistry mix and separate different types of solutions various mixtures introduction to solutions

an organic liquid (A), containing C,H and O with boiling point $78^{\circ}$C and possessing a rather pleasant odour or heating with concenterated $H _{2}SO _{4}$ gives a gaseous product (B) with the empirical formula $CH _{2}$. B decolourises bromine water as well as alkaline $KMnO _{4}$ solution and takes up one mole of $H _{2}$(per mole of B) in the presence of finely divided nickle at high temperature. A and B are:

  1. $C _{2}H _{5}OH$, $C _{2}H _{2}$
  2. $CH _{3}OH$, $C _{2}H _{2}$
  3. $C _{2}H _{5}OH$, $C _{2}H _{4}$
  4. $(CH _{3}) _{2}CHOH$, $C _{3}H _{6}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$C _2H _5OH$ or ethyl alcohol when treated with concentrated $H _2SO _4$ undergoes dehydration to form ethene($C _2H _4$). Ethane reacts with alkaline $KMnO _4$ undergoes oxidation to form ethylene glycol. Ethene  undergoes hydrogenation in presence of nickel heads of one mole of $H _2$ to form ethane.

The correct option is C

Multiple choice chemistry polymer addition polymerisation types of polymerisation reactions petrochemicals and polymers

Which of the following free radicals is the most stable ?

  1. primary

  2. methyl

  3. secondary

  4. tertiary
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Electron poor species are stabilized by neighboring atoms that can donate electron density. The most common way to interpret rich neighbors here is the observation that increasing the number of alkyl groups on the carbon bearing the free radical increases its stability. 


Radical stability increases in the order methyl < primary < secondary < tertiary. 

Hence, option $D$ is correct.

Multiple choice chemistry polymer addition polymerisation types of polymerisation reactions petrochemicals and polymers

Which of the following are used as free radical chain initiators ?

  1. Benzoyl peroxide

  2. di-tert-butyl peroxide

  3. Carbon tetrachloride

  4. Benzoquinone
Reveal answer Fill a bubble to check yourself
A,B Correct answer
Explanation

A radical initiator is a species that acts as the reactant of the initiation step of a radical chain reaction but does not participate in any of the propagation steps.
Radical initiators are substances that can produce radical species under mild conditions and promote radical reaction. These substances generally possess weak bonds that have small bond dissociation energy. Radical initiators are utilized in industrial processes such as polymer synthesis. Typical examples are halogen molecules, azo compounds and organic and inorganic peroxides such as Benzoyl peroxide, di- t-Butyl peroxide.