Chemistry
Chemical Bonding and Molecular Structure
1,277 Questions
This section tests your knowledge of chemical bonding, molecular structure, and hybridization. It covers ionic and covalent bonds, octet rule exceptions, and molecular geometry. These chemistry questions are common in various competitive entrance examinations.
Ionic and covalent bondsHybridisation of elementsOctet rule exceptionsMolecular geometryIntermolecular forces
Chemical Bonding and Molecular Structure Questions
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Sodium dissolved in ammonia conducts electricity.
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The metallic lustre exhibited by sodium is due to the existence of body centered cubic lattice.
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Sodium sulphate is soluble in water.
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Sodium oxide is ionic in nature.
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Sodium does not exist in free state in nature.
B
Correct answer
Explanation
This statement is incorrect. The metallic lustre of any metal is due to the presence of oscillating free electrons in the metal.
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BH3 and NH3
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PCl5 and IF5
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NH4+ and SF4
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CO32- and NO3-
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BeH2 and H2O
D
Correct answer
Explanation
CO32-: Trigonal planar
NO3-: Trigonal planar
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2 single bond, one double bond
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4 single bond, one triple bond
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4 single bond, one double bond
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4 single bond only
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One double only
C
Correct answer
Explanation
The formula of ethene is CH2=CH2, between C and H is formed a single bond and C and C formed double bond.
4C-H = 4 x 1 = 4 and C-C = 1 double bond.
B
Correct answer
Explanation
MgCl2 is ionic compound and strong intermolecular force of attraction. As a result, ionic compounds have high melting and boiling points.
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B6N6H10 and B5N5H8
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B3N3H3Br3 and B5N5H8
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B3N3H3Cl3 and B3N3H3Br3
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B3N3H3Cl3 and B6N6H10
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None of these
A
Correct answer
Explanation
This option is correct because when borazole is pyrolysed above 3400C, it produces analogues compounds in the form of diphenyl and naphthalene like B6N6H10 and B5N5H8.
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A and B
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C and D
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A and E
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B and E
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C and B
C
Correct answer
Explanation
H atom completes its duplet, not octet.
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Only A
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Only B
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Only C
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1 and 2
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2 and 3
B
Correct answer
Explanation
Hybridization of ‘S’ is number of atomic orbitals involved in hybridization = 1/2 (no. of e- in outer most shell + no. of e- in σ bonds – no. of e- in π bonds) = 1/2(6 + 1 - 1) = 3. Out of the three orbitals, one is s and two are p-orbitals, hence the hybridization os ‘S’ is sp2.
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1s2
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1s2, 2s2 2p2
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1s2, 2s2 2p5
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1s2, 2s2 22
C
Correct answer
Explanation
Configuration 1s2 2s2 2p5 represents fluorine (7 valence electrons), one electron short of octet. It can either share an electron (covalent, as in F2) or gain one (ionic, forming F-). Option A is helium (noble gas), B is carbon (forms only covalent bonds), and D has a typo in notation.
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Calcium chloride
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Carbon monoxide
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Sulphur dioxide
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Ethanol
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Acetone
A
Correct answer
Explanation
Calcium chloride is solid in nature.
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Ammonium chloride
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Sodium chloride
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Iodine
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Naphthalene
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hydration
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acidification
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dissociation
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neutralization
C
Correct answer
Explanation
The process of breaking of a solid ionic compound into its constituent ions is called dissociation.
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Nitrogen
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Zinc
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Bromine
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Iodine
B
Correct answer
Explanation
Zinc is the odd one out because it is the only metal in the list. Nitrogen, Bromine, and Iodine are all non-metals (Nitrogen is a gas, Bromine and Iodine are halogens). Zinc is a transition metal with typical metallic properties: luster, conductivity, and malleability.
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Phosphorous
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Chlorine
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Nitrogen
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Neon
D
Correct answer
Explanation
Neon is a noble gas. It exists in monoatomic state.
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Hydrogen chloride
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Acetic acid
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Ozone
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Water
C
Correct answer
Explanation
Ozone [O3 ] is a molecule of an element, i.e. oxygen.