Multiple choice

The hybridization of sulphur shown in sulphur dioxide is:

  1. sp

  2. sp2

  3. sp3

  4. sp3d

  5. dsp2
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Hybridization of ‘S’ is number of atomic orbitals involved in hybridization = 1/2 (no. of e- in outer most shell + no. of e- in σ bonds – no. of e- in π bonds) = 1/2(6 + 1 - 1) = 3. Out of the three orbitals, one is s and two are p-orbitals, hence the hybridization os ‘S’ is sp2.

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