Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

Four years ago ratio of age of Saumya and Raveena was (8:11). Four year hence ratio of their age will be (4:5). Find the sum of their present ages.

  1. 42

  2. 46

  3. 48

  4. 45

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let present ages be S (Saumya) and R (Raveena). Four years ago: (S - 4)/(R - 4) = 8/11, giving 11S - 8R = 12. Four years hence: (S + 4)/(R + 4) = 4/5, giving 5S - 4R = -4. Solving simultaneously: From second equation, S = (4R - 4)/5. Substituting in first: 11(4R - 4)/5 - 8R = 12, which gives (44R - 44 - 40R)/5 = 12, so 4R - 44 = 60, R = 26. Then S = (104 - 4)/5 = 20. Sum = 20 + 26 = 46.

Multiple choice

Seven years ago, the ratio of the age of Aniruddh to that of Bhavna, was 7 : 9. Chandranshu is 12 years older than Aniruddh and 12 years younger than Bhavna. What is Chandranshu's present age?

  1. 93 years

  2. 103 years

  3. 110 years

  4. 113 years

  5. 105 years
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Seven years ago, Aniruddh:Bhavna = 7:9, so A-7 : B-7 = 7:9. Chandranshu is 12 years older than Aniruddh (C = A + 12) and 12 years younger than Bhavna (C = B - 12). This means B - A = 24. From the ratio: (A-7)/(B-7) = 7/9. Substituting B = A+24: (A-7)/(A+17) = 7/9. Cross-multiplying: 9A-63 = 7A+119. So 2A = 182, A = 91. Therefore C = 91 + 12 = 103 years.

Multiple choice

Sunil’s present age is four times his son’s present age and four-seventh of his father’s present age. The average of the present ages of all three of them is 32 years. What is the difference between the Sunil’s son’s present age and Sunil’s father’s present age? सुनील की वर्तमान आयु उसके पुत्र की वर्तमान आयु का चार गुना है और अपने पिता की वर्तमान आयु का चार सप्तमांश है। सभी की वर्तमान आयु का औसत 32 वर्ष है। सुनील के पुत्र की वर्तमान आयु और सुनील के पिता की वर्तमान आयु में क्या अन्तर है ?

  1. 44 years/वर्ष

  2. 46 years/वर्ष

  3. 48 years/वर्ष

  4. 54 years/वर्ष
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let son's age be x. Then Sunil = 4x, and Sunil = (4/7) × father's age, so father = 7x. Average = (x + 4x + 7x)/3 = 32, so 12x = 96, giving x = 8. Father is 56, son is 8. Difference = 56 - 8 = 48 years. Option C (48 years) is correct.

Multiple choice

What is the difference between the ages of Preeti and Veeru after 5 years? I. The ratio between their present ages is 4 : 7. II. After 6 years, Veeru's age will be 1.5 times the Preeti's age. III. 5 years ago, the ratio of their ages was 7 : 16.

  1. Any two

  2. I and III

  3. II and III

  4. All three together are sufficient

  5. All three together are not sufficient
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

From I: P:V = 4:7, so P=4x, V=7x. From II: (V+6) = 1.5(P+6), so 7x+6 = 1.5(4x+6) = 6x+9, giving x=3. So P=12, V=21, difference=9. From III: (P-5):(V-5) = 7:16. With P=4x, V=7x: (4x-5):(7x-5) = 7:16 gives 16(4x-5)=7(7x-5), so 64x-80=49x-35, giving 15x=45 or x=3. So P=12, V=21, same answer. Checking I+III: 4x-5:7x-5=7:16 gives x=3, which works. Any two statements are sufficient.

Multiple choice

The ratio of A and B is 3 : 4. After 12 years B's age become 20% more than present age. Find after 5 years, age of B will be what percent more than age of A. A और B की आयु का अनुपात 3 : 4 है । 12 वर्ष बाद B की आयु उसकी वर्तमान आयु से 20% अधिक हो जायेगी । ज्ञात कीजिये 5 वर्ष के बाद, B की आयु, A की आयु से कितने प्रतिशत अधिक होगी ?

  1. 30%

  2. 40%

  3. 50%

  4. 15%
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let A = 3x, B = 4x. After 12 years, B = 4x + 12 = 1.2 × 4x = 4.8x. Solving: 4x + 12 = 4.8x gives 12 = 0.8x, so x = 15. Present ages: A = 45, B = 60. After 5 years: A = 50, B = 65. B is (65-50)/50 × 100 = 30% more than A. The key is first finding B's present age using the 20% increase information.

Multiple choice

The average age of Jai and his son is 20% more than the average age of his wife and his son. The age of son is 32 years less than the age of his mother, Age of Jai is 8 years more than his wife's age. Find the age of Jai's son?

  1. 8 year

  2. 5 year

  3. 4 year

  4. Can't be determine.

  5. None of these.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let son's age = s, mother's age = m, Jai's age = j. Given: m-s = 32, j = m+8. Average of Jai and son = (j+s)/2, average of wife and son = (m+s)/2. The first is 20% more: (j+s)/2 = 1.2×(m+s)/2. Simplify: j+s = 1.2m + 1.2s. Substitute j = m+8: m+8+s = 1.2m+1.2s, so 8 = 0.2m + 0.2s, or m+s = 40. With m-s = 32, adding gives 2m = 72, so m = 36. Then s = 4.

Multiple choice

What is the age of Rahul? Statement I : The ratio of present age of Kailash and Rahul is 3 : 5 and 4 years before Kailash was 8 years younger than Rahul. Statement II : 3 years ago the ratio of ages of Kailash and Rahul was 4 : 7 and 3 years hence the ratio will become 2 : 3.

  1. Only I

  2. Only II

  3. Either I or II

  4. Both together

  5. Both together are sufficient
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Statement I: Kailash:Rahul = 3:5. Let Kailash=3x, Rahul=5x. 4 years ago: 3x-4 = 5x-4-8, giving 3x-4 = 5x-12, so 2x=8, x=4. Thus Rahul=20 years - sufficient. Statement II: 3 years ago ratio was 4:7, and 3 years hence ratio will be 2:3. Let ages be K and R. (K-3)/(R-3)=4/7 and (K+3)/(R+3)=2/3. These two equations can be solved for K and R independently. Both statements alone are sufficient, making 'Either I or II' correct.

Multiple choice

The ages of Ajay and Vijay are in the ratio 9 : 5 . After eight years the ratio of their ages will be 13 : 9. What is the difference between their present ages? अजय और विजय की आयु में 9 : 5 का अनुपात है। आठ वर्षो बाद उनकी आयु का अनुपात 13 : 9 हो जाएगा। उनकी वर्तमान आयु के बीच क्या अंतर है?

  1. 8 years/वर्ष

  2. 12 years/वर्ष

  3. 9 years/वर्ष

  4. 6 years/वर्ष
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let present ages be 9x and 5x. After 8 years: (9x+8)/(5x+8) = 13/9. Cross-multiplying: 81x + 72 = 65x + 104, so 16x = 32 and x = 2. Present ages are 18 and 9, difference = 9. Wait - that gives 9, not 8. Let me recalculate: (9x+8)/(5x+8) = 13/9. 9(9x+8) = 13(5x+8). 81x + 72 = 65x + 104. 16x = 32. x = 2. Ages: 9×2=18, 5×2=10. Difference = 8 years. Option A is correct. Option C (9 years) is a common error from mis-solving.

Multiple choice

Four years ago, the ratio of the ages of P and Q was 13 : 9 and eight years hence, it would be 4 : 3. The difference of their present ages is

  1. 56 years

  2. 40 years

  3. 16 years

  4. 24 years

  5. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let ages 4 years ago be 13x and 9x, so current ages are 13x+4 and 9x+4. After 8 years: (13x+12)/(9x+12) = 4/3. Solving gives 39x+36 = 36x+48, so 3x=12 and x=4. Current ages are 56 and 40, difference is 16 years. Option C is correct.

Multiple choice

The ratio of age of A and B. 2 year ago was 9 : 5. After 1 year this ratio become 7 : 4. What is the presentage of B. 2 वर्ष पूर्व A तथा B की आयु का अनुपात 9 : 5 था। एक वर्ष बाद यह अनुपात 7 : 4 हो गया। B की वर्तमान आयु ज्ञात कीजिए?

  1. 48 year/वर्ष

  2. 47 year/वर्ष

  3. 38 year/वर्ष

  4. 58 year/वर्ष
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let present ages be A and B. Two years ago: (A-2)/(B-2) = 9/5, so 5A - 10 = 9B - 18, giving 5A = 9B - 8. After one year: (A+1)/(B+1) = 7/4, so 4A + 4 = 7B + 7, giving 4A = 7B + 3. Solving: From 5A = 9B - 8, A = (9B - 8)/5. Substituting in 4A = 7B + 3: 4(9B - 8)/5 = 7B + 3, giving 36B - 32 = 35B + 15, so B = 47. Present age of B is 47 years.

Multiple choice

The ratio of the age of Ajay and his daughter is 11 : 3. 'N' year ago the the sum their ages decreased by 20 year while the ratio of their ages then was 17 : 1. Find the value of N. अजय और उसकी बेटी की आयु का अनुपात 9 : 4 है । 'N' वर्ष पहले उनकी आयु का योग 20 वर्ष कम हो गया, जबकि उस समय उनकी आयु का अनुपात 17 : 1 था। तो N का मान ज्ञात कीजिये ?

  1. 20

  2. 15

  3. 10

  4. 30
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The English text states ratio 11:3 but Hindi says 9:4 - this is a discrepancy. Checking with 11:3: Let Ajay=11x, daughter=3x. N years ago: (11x-N)+(3x-N) = 14x-2N. Current sum = 14x. So (14x) - (14x-2N) = 20 gives N=10. Check ratio at N=10: (11x-10):(3x-10) = 17:1. Solving gives x=5. So N=10 works with English text. Hindi text likely has a typo.

Multiple choice

4 years ago ratio of age of Sudhir and his son Ramesh was 8 : 1. 4 year hence ratio of age of Sudhir and him wife Sujata will be 10:9. If Sujata is 24 years elder to her son Ramesh. Find the present age of Sudhir.

  1. 32 years

  2. 34 years

  3. 36 years

  4. 40 years

  5. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let present ages: Sudhir = S, Ramesh = R, Sujata = J. 4 years ago: (S-4):(R-4) = 8:1, so S-4 = 8(R-4), S = 8R - 28. 4 years hence: (S+4):(J+4) = 10:9, so 9(S+4) = 10(J+4). Sujata is 24 years elder than Ramesh: J = R + 24. Substitute J: 9S + 36 = 10R + 280. Substitute S from first equation: 9(8R-28) + 36 = 10R + 280, so 72R - 252 + 36 = 10R + 280, 62R = 496, R = 8. Then S = 8(8) - 28 = 36.