Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

The ratio of present ages of A and B is 7:5. After 26 years the ratio of their ages will be in ratio 10:9. At present, what is the age of B? A और B के वर्तमान आयु का अनुपात 7: 5 है । 26 वर्षों के बाद उनकी आयु का अनुपात 10: 9 होगा। वर्तमान में, B की आयु क्या है?

  1. 5

  2. 10

  3. 24

  4. 14
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let present ages be 7x and 5x. After 26 years: (7x+26)/(5x+26) = 10/9. Cross-multiply: 9(7x+26) = 10(5x+26), giving 63x+234 = 50x+260, so 13x=26 and x=2. B's present age = 5x = 10 years.

Multiple choice

7 years ago, Varun's age was five times the square of Swati's age. 3 years hence, Swati's age will be two-fifth of Varun's age. Find Swati's present age.

  1. 10 years

  2. 27years

  3. 7 years

  4. 9 years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let Varun's present age = x, Swati's present age = y. 7 years ago: (x-7) = 5(y-7)². 3 years hence: (y+3) = (2/5)(x+3). From second equation: 5y + 15 = 2x + 6 → 2x = 5y + 9 → x = (5y+9)/2. Testing y=9: x = (45+9)/2 = 27. Check first equation: (27-7) = 5(9-7)² → 20 = 5(4) → 20 = 20 ✓. Swati is 9 years old. Option D is correct.

Multiple choice

Ten years ago, Manisha was half of Atul in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages? दस वर्ष पहले, मनीषा की आयु अतुल की आयु का आधा थी। यदि उनकी वर्तमान आयु में अनुपात 3 : 4 है, उनकी वर्तमान आयु का योग क्या होगा?

  1. 33 years/ 33 वर्ष

  2. 37 years/ 37 वर्ष

  3. 35 years/ 35 वर्ष

  4. 41 years/ 41 वर्ष
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let present ages be 3x and 4x. Ten years ago: 3x - 10 = 0.5(4x - 10). Solving gives x = 5, so total age = 7x = 35 years. Option C is correct.

Multiple choice

The sum of the age of a father and the age of his son is 75 years. If the product of their ages before 5 years was 750, then what is the present age of son?

  1. 30 years

  2. 55 years

  3. 25 years

  4. 20 years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let present ages be f (father) and s (son). f + s = 75. Five years ago: (f-5)(s-5) = 750. Substituting f = 75-s: (70-s)(s-5) = 750. Expanding: 70s - 350 - s² + 5s = 750. Rearranging: s² - 75s + 1100 = 0. Solving: s = 25 or s = 44. But if s = 44, then f = 31 (impossible as father must be older). Thus s = 25. Checking: ages 5 years ago were 50 and 20, product = 1000, not 750. There's an error. Let son = 20, father = 55. Five years ago: 50 × 15 = 750. This works! Son is 20 years. Option D is correct.

Multiple choice

The average age of a husband – wife and their son was 42 years. The son got married and exactly after 1 year child was born to them. When the child became 5 years old, the average age of the family became 36 years. What was the age of bride at the time of marriage?

  1. 26 years

  2. 25 years

  3. 34 years

  4. 23 years

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Initial family: husband, wife, son. Average age = 42, so total = 3 × 42 = 126. Son marries → family now has 4 people. After 1 year, child is born → 5 people. When child is 5 years old, 6 years have passed since son's marriage. New total age = 126 + 6 + (bride's age + 5) = 5 × 36 = 180. So bride's age + 131 = 180, bride's age at that time = 49. At marriage (6 years earlier), bride was 49 - 6 = 25 years old. Track time passage and total age changes carefully.

Multiple choice

6 years ago age of father was 3.5 times of the age of son. 10 years hence age of father will become 2.5 times of age of Son. Find the sum of their present ages.

  1. 112

  2. 125

  3. 120

  4. 118

  5. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let present ages be F (father) and S (son). 6 years ago: F-6 = 3.5(S-6) → F = 3.5S - 15. 10 years hence: F+10 = 2.5(S+10) → F = 2.5S + 15. Equating: 3.5S - 15 = 2.5S + 15 → S = 30, F = 90. Sum = 120. Option C is correct.

Multiple choice

My grandmother was 9 times as old as me, 16 years ago. She would be 3 times of my age, 8 years from now. Eight years ago, what was the ratio of my age to that of my grandmother?

  1. 3: 8

  2. 1: 5

  3. 1: 2

  4. 2: 5

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let current ages be G (grandmother) and M (me). 16 years ago: G - 16 = 9(M - 16) → G = 9M - 128. 8 years from now: G + 8 = 3(M + 8) → G = 3M + 16. Equating: 9M - 128 = 3M + 16 → 6M = 144 → M = 24. Then G = 3(24) + 16 = 88. 8 years ago: M = 16, G = 80. Ratio = 16:80 = 1:5.

Multiple choice

The ages of Shyam and Mohan are in the ratio of 11 : 13 respectively. After 7 years the ratio of their ages will be 20 : 23. What is the difference in years between their ages?

  1. 4 years

  2. 7 years

  3. 6 years

  4. 5 years
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let Shyam's age = 11x and Mohan's age = 13x, so their difference = 2x. After 7 years: (11x+7)/(13x+7) = 20/23. Cross-multiply: 253x + 161 = 260x + 140, which gives 7x = 21, so x = 3. The difference in their ages = 2x = 6 years, which is constant throughout their lives. Option C is correct.

Multiple choice

Samir’s age is one – fourth of his father’s age and two – third of his sister Reema’s age. What is the ratio of the ages of the Samir, Reema and their father respectively? समीर की उम्र उसके पिता की उम्र का एक चौथाई और उसकी बहन रीमा की उम्र का दो-तिहाई है। समीर, रीमा और उनके पिता की उम्र का अनुपात क्रमशः क्या है?

  1. 3: 2: 8

  2. 3: 4: 8

  3. 2: 3: 8

  4. 4: 3: 8
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let Samir's age = S, Reema's age = R, father's age = F. Given: S = F/4 and S = 2R/3. Express all in terms of S: F = 4S, R = 3S/2. Ratio S:R:F = S : 3S/2 : 4S = 2 : 3 : 8 (multiplying by 2 to clear fraction).

Multiple choice

The present age of a father is 4 years more than seven times the age of his son. Six years hence, father's age will be 8 years more than thrice the age of the son. Find the present age of the father.

  1. 28 years

  2. 30 years

  3. 34 years

  4. 32 years

  5. 36 years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let son's present age = x. Then father's present age = 7x + 4. Six years hence: (7x + 4) + 6 = 3(x + 6) + 8. Solving: 7x + 10 = 3x + 26. Therefore 4x = 16, x = 4. Father's present age = 7(4) + 4 = 32 years.

Multiple choice

If 6 is subtracted from the age of Sakshi's grandfather and then divided by 18, age of Saumya is obtained. If Sakshi's age after 8 years is 13 years and she is 2 years older than his brother Saumya. Then what is her grandfather's age after 4 years ? यदि साक्षी के दादाजी की आयु से 6 घटा दिया जाता है और फिर इसे 18 से विभाजित किया जाता है, सौम्य की आयु प्राप्त होती है। यदि साक्षी की आयु 8 वर्ष बाद 13 वर्ष है और वह अपने भाई सौम्य से 2 वर्ष बड़ी है। तो उसके दादाजी की आयु 4 वर्ष के बाद क्या है ?

  1. 60 years/वर्ष

  2. 64 years/वर्ष

  3. 56 years/वर्ष

  4. 54 years/वर्ष
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Sakshi's age after 8 years = 13, so her current age = 5. Saumya is 2 years younger, so his age = 3. From the relationship: (Grandfather's age - 6)/18 = 3. Therefore Grandfather's age = 3 × 18 + 6 = 60. After 4 years, grandfather's age = 60 + 4 = 64 years.

Multiple choice

Six years hence a father's age will be three times his son's age and three years ago father was nine times as old as his son. What is the present age of father? छः वर्ष बाद एक पिता की आयु अपने पुत्र की आयु की तीन गुना होगी और तीन वर्ष पहले पिता अपने पुत्र से नौ गुना बड़ा था। पिता की वर्तमान आयु क्या है?

  1. 48 years/वर्ष

  2. 42 years/वर्ष

  3. 36 years/वर्ष

  4. 30 years/वर्ष
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let father's present age = F, son's present age = S. Six years hence: F+6 = 3(S+6), so F = 3S+12. Three years ago: F-3 = 9(S-3), so F = 9S-24. Equating: 3S+12 = 9S-24, giving 6S = 36 and S = 6. Therefore F = 3×6+12 = 30 years.

Multiple choice

Three years ago, the average age of a family of 8 members was 30 years. If one child is also included in the family, the present age of the family remained unchanged. What is present age of the child? तीन वर्ष पहले एक परिवार के 8 सदस्यों की औसत आयु 30 वर्ष थी। यदि परिवार में एक बच्चे को सम्मिलित कर लिया जाए तो परिवार का वर्तमान औसत समान रहता है। बच्चे की वर्तमान आयु क्या है?

  1. 6 year/वर्ष

  2. 1 year/वर्ष

  3. 3 year/वर्ष

  4. 4 year/वर्ष
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Three years ago, average age of 8 members = 30 years, so total age = 8×30 = 240 years. Present total age of those 8 members = 240 + (8×3) = 264 years. When child (age x) is added, total members = 9 and total age = 264 + x. New average = (264+x)/9 = 30 (unchanged). Therefore 264+x = 270, so x = 6 years.

Multiple choice

The sum of the ages of a son and father is 56 years. After four years, the age of the father will be three times that of the son. Find the difference between their respective ages. एक पिता और पुत्र की आयु का योग 56 वर्ष है। चार वर्ष बाद, पिता की आयु पुत्र की आयु का तीन गुना हो जायेगी। उनकी आयु में अन्तर ज्ञात कीजिए।

  1. 30 years/वर्ष

  2. 32 years/वर्ष

  3. 34 years/वर्ष

  4. 36 years/वर्ष
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let son's age = s, father's age = f. Given s + f = 56 and f + 4 = 3(s + 4). Substituting: f = 56 - s, so 60 - s = 3s + 12, 4s = 48, s = 12, f = 44. Difference = 44 - 12 = 32 years.