The average age of Jai and his son is 20% more than the average age of his wife and his son. The age of son is 32 years less than the age of his mother, Age of Jai is 8 years more than his wife's age. Find the age of Jai's son?

Let son's age = s, mother's age = m, Jai's age = j. Given: m-s = 32, j = m+8. Average of Jai and son = (j+s)/2, average of wife and son = (m+s)/2. The first is 20% more: (j+s)/2 = 1.2×(m+s)/2. Simplify: j+s = 1.2m + 1.2s. Substitute j = m+8: m+8+s = 1.2m+1.2s, so 8 = 0.2m + 0.2s, or m+s = 40. With m-s = 32, adding gives 2m = 72, so m = 36. Then s = 4.