Tag: compounds of phosphorus- pcl5

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Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

A translucent white waxy solid (A) reacts with excess of chlorine to give a yellowish white powder (B). (B) reacts with organic compounds containing -OH group converting them into chloro derivatives. (B) on hydrolysis gives (C) and is finally converted to phosphoric acid. (A), (B) and (C) are?

  1. $P _{4}$,$PCl _{3}$,$H _{3}PO _{4}$
  2. $P _{4}$,$PCl _{5}$,$H _{3}PO _{3}$
  3. $P _{4}$,$PCl _{5}$,$POCl _{3}$
  4. $P _{4}$,$PCl _{3}$,$POCl _{3}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

A translucent white waxy solid (A) reacts with excess of chlorine to give a yellowish white powder (B). Here B is $PCl _5$.$PCl _5$ reacts with organic compounds containing -OH group converting them into chloro derivative $POCl _3. $.$PCl _5$ on hydrolysis gives (C).C is $POCl _3$ and is finally $POCl _3$ converted to phosphoric acid.

So  (A), (B) and (C) are $P _{4}$,$PCl _{5}$,$POCl _{3}$.

Hence option C is correct.

Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

$\mathrm{P}\mathrm{Cl} _{3}$ is prepared by the action of $\mathrm{Cl} _{2}$ on :

  1. $ \mathrm{P} _{2}\mathrm{O} _{3}$
  2. $ \mathrm{P} _{2}\mathrm{O} _{5}$
  3. White $\mathrm{P}$
  4. $\mathrm{H} _{3}\mathrm{P}\mathrm{O} _{3}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

White P is reactive due to strain.
$P _{4}+6Cl _{2}\ \to \ 4PCl _{3}$
(White P)

Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

What is the oxidation state of Phosphorus in ${P}{Cl} _{3}$?

  1. ${+}{5}$
  2. ${+}{3}$
  3. ${+}{1}$
  4. ${-}{3}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The oxidation state of ${P}$ in ${P}{Cl} _{3}$ is ${+3}$.
Each Chlorine atom has an oxidation number of ${-1}$. There are three chlorine atoms, hence the total oxidation number of the Chloride ions in ${-3}$. ${PCl} _{3}$ molecule is neutral. Hence the oxidation number of Phosphorus should be ${+3}$

Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

What is the hybridization of Phosphorus Trichloride?

  1. ${sp}^{3}$
  2. ${sp}^{2}$
  3. ${sp}$

  4. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The hybridization of ${PCl} _{3}$ is ${sp}^{3}$. Phosphorus has five electrons in its outermost shell. Thus it forms three sigma bonds with three neighbouring Chlorine atoms. The remaining two electrons remain as a lone pair on Phosphorus atom. Thus these three sigma bonds and one lone pair, make this molecule ${sp}^{3}$ hybridized.

Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

What kind of a molecule is ${P}{Cl} _{3}$?

  1. Ionic

  2. Polar covalent

  3. Non polar covalent

  4. none of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$PCl _3$ is a polar covalent molecule. It is polar because chlorine atoms are more electronegative than phosphorus atom and hence the polartity of the molecule is towards Chlorine atoms.
It is covalent because, Phosphorus has ive electrons in its outermost shell. It requires three more to complete its octet. Each chlorine atom has seven electrons in their outermost shell, they all require one electron each to complete their octet. Thus both phosphorus and chlorine complete their octet by mutually sharing their electrons. Hence this molecule is polar covalent in nature.

Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

What is produced as an impurity during the production of ${PCl} _{3}$:

  1. ${PCl} _{5}$
  2. ${POCl} _{3}$
  3. ${PSCl} _{3}$
  4. ${Cl} _{2}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

During the indusrial preparation of ${PCl} _{3}$, ${PCl} _{5}$ or Phosphorus Pentachloride is produced as an impurity. The balanced equation can be written as-
${PCl} _{3}$ ${+}$ ${Cl} _{2}$ ${=}$ ${PCl} _{5}$
Thus this impurity formation can be stopped by continual removal of ${PCl} _{3}$ as it is formed.

Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

Aqueous solution of PBr$ _{3}$ conducts electricity due to the presence of:

  1. $\mathrm{HOBr}$
  2. $\mathrm{HBr}$
  3. $\mathrm{H} _{3}\mathrm{P}\mathrm{O} _{4}$
  4. $\mathrm{H} _{2}\mathrm{O}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$PBr _{3}+3H _{2}O\ \to \ H _{3}PO _{4}+HBr$
HBr is covalent $H _{3}PO _{4}$ is ionic. Solution conducts electricity due to ions.
So aqueous solution of $PBr _{3}$ conducts electricity due to presence of $H _{3}PO _{4}$.