Tag: compounds of phosphorus- pcl5

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Multiple choice chemistry p- block elements-ii compounds of phosphorus- pcl5 phosphorus halides compounds of phosphorus compounds of phosphorus - pcl3

The hybrid states of phosphorous atoms in $PCl _{5}$ and $PBr _{3}$ in gaseous phase are $sp^{3}d$. But in solid $PCl _{5}$, phosphorous shows $sp^{3}d^2$ hybrid state. While $P$ in $PBr$ is in $sp^{3}$ hybrid state. This is because :

  1. $PCl _{5}$ in solid form exists as $[PCl _{4}]^{+}[PCl _{6}]^{-}$
  2. $PBr _{5}$ in solid form exists as $[PCl _{4}]^{+}[PBr _{6}]^{-}$
  3. $PCl _{5}$ in solid form exists as $[PCl _{4}]^{+}Cl^{-}$
  4. $PBr _{5}$ in solid form exists as $[PBr _{4}]^{+}Br^{-}$
Reveal answer Fill a bubble to check yourself
A,D Correct answer
Explanation
Both $PCl _{5}$ and $PBr _{5}$ have triagonal bipyramidal geometry this is not  a regular structure and is not very stable.

Therefore $PCl _{5}$ splits up into two more stable octahedral and tetrahedral  structures .

$PCl _{5}$ in solid form exists as $[PCl _{4}]^{+}[PCl _{6}]^{-}$. The hybridisation state of $P$ in $[PCl _{4}]^{+}$ and $[PCl _{6}]^{-}$ is 
$sp^3$ and $sp^3d^2$ respectively.

$PBr _{5}$ in solid form exists as $[PBr _{4}]^{+}Br^{-}$ and hybridisation state of $P$ in $[PBr _{4}]^{+}$ is $sp^3$ hybridised.
Multiple choice chemistry p- block elements-ii compounds of phosphorus- pcl5 phosphorus halides compounds of phosphorus compounds of phosphorus - pcl3

Identify the correct statements.

  1. Calcium cyanamide on treatment with steam under pressure gives ${NH _3}$ and ${Ca CO _3}$
  2. ${PCl _5}$ is kept in well stopped bottle because it reacts readily with moisture

  3. Ammonium nitrite on heating gives ammonia and nitrous acid
  4. Cane sugar reacts with conc. ${H NO _3}$ to form oxalic acid
Reveal answer Fill a bubble to check yourself
A,B,D Correct answer
Explanation

(A) Calcium cyanamide on treatment with steam under pressure gives ${NH _3}$ and ${Ca CO _3}$
 $\displaystyle CaCN _2+3H _2O \text { (steam)} \xrightarrow {\displaystyle \text {3 atm}} CaCO _3+ 2NH _3$
(B) ${PCl _5}$ is kept in well stopped bottle because it reacts readily with moisture
 $\displaystyle PCl _5+H _2O \rightarrow POCl _3+2HCl$
 $\displaystyle PCl _5+4H _2O \rightarrow H _3PO _4+5HCl$
(C) Ammonium nitrite on heating gives nitrogen and water.
 $\displaystyle NH _4NO _2 \rightarrow N _2  +2H _2O$
(D)Cane sugar reacts with conc. ${H NO _3}$ to form oxalic acid
 $\displaystyle C _{12}H _{22}O _{11}+36HNO _3 \rightarrow 6(COOH) _2+36NO _2+23H _2O$

Multiple choice chemistry p- block elements-ii compounds of phosphorus- pcl5 phosphorus halides compounds of phosphorus compounds of phosphorus - pcl3

Choose the correct options:

  1. PCl$ _5$ (solid) dissociates into PCl$ _4^+$ and PCl$ _6^-$.
  2. LiH reacts with AlH$ _3$ forming LiAlH$ _4$.
  3. $NH _3$ is protonated.
  4. $H _3PO _2$ on heated forms $PH _3$ and $H _3PO _3$.
Reveal answer Fill a bubble to check yourself
A,B Correct answer
Explanation

PCl$ _5$ (solid) dissociates into PCl$ _4^+$ and PCl$ _6^-$. LiH reacts with AlH$ _3$ forming LiAlH$ _4$. These are facts. $NH _3$ is not protonated. On protonation, it forms $NH _4^+$ion. $H _3PO _2$ on heating does not form $PH _3$ and $H _3PO _3$.

Multiple choice chemistry p- block elements-ii compounds of phosphorus- pcl5 phosphorus halides compounds of phosphorus compounds of phosphorus - pcl3

In the given reaction $CI$  replaces one of the H-atoms in $CH _3CH _2OH$. This $H$ is of :


$PCI _5+C\underset{\overline{X}}{H _3}C\underset{\overline{Y}}{H _2}\underset{\overline{Z}}{OH} \longrightarrow$

  1. C (in X)

  2. C (in Y)

  3. O (in Z)

  4. any of X, Y and Z
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

In the reaction of ethanol (CH3CH2OH) with PCl5, the hydroxyl group (-OH) is replaced by a chlorine atom. This involves the breaking of the O-H bond (Z position) and the C-O bond.

Multiple choice chemistry p- block elements-ii compounds of phosphorus- pcl5 phosphorus halides compounds of phosphorus compounds of phosphorus - pcl3

The solid $PCl _5$ exists as :

  1. $PCl _3$
  2. $PCl _4^+$
  3. $PCl _6^-$
  4. $PCl _4^+$ and $PCl _6^-$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

In solid state, $PCl _5$  prefers to exist as oppositely charged ions like $[PCl _4]^+$ & $[PCl _6]^-$ as the ionic bonding enhances the crystalline nature.

Also, $[PCl _4]^+$ is tetrahedral while $[PCl _6]^-$ is octahedral, these structures fit well into each other providing extra stability to the soild structure.

Multiple choice chemistry p- block elements-ii compounds of phosphorus- pcl5 phosphorus halides compounds of phosphorus compounds of phosphorus - pcl3

Solid crystalline $PCI _5$ has structure which of the following?

  1. Bi-pyramidal

  2. Octahedral and tetrahedral ions

  3. Square-pyramidal

  4. Pentagonal

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

In solid state, $PCl _5$ prefers to exist as oppositely charged ions like $[PCl _4]^+$ & $[PCl _6]^-$ as the ionic bonding enhances the crystalline nature. Also, $[PCl _4]^+$ is tetrahedral while $[PCl _6]^-$ is octahedral, these structures fit well into each other providing extra stability to the soild structure.

Multiple choice chemistry p- block elements-ii compounds of phosphorus- pcl5 phosphorus halides compounds of phosphorus compounds of phosphorus - pcl3

In crystalline state $PCl _5$ exists as :

  1. $[PCl _4]^+Cl^-$
  2. $[PCl _4]^+[PCl _6]^-$
  3. $[PCl _3]^{2+}+2Cl^-$
  4. $[PCl _6]^+[PCl _4]^-$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

In solid state, $PCl _5$ prefers to exist as oppositely charged ions like $[PCl _4]^+ [PCl _6]^-$ as ionic bonding enhances the crystalline nature. Also, $[PCl _4]^+$ is tetrahedral while $[PCl _6^-]$ is octahedral. These structures fit well into each other providing extra stability to the solid structure.


Hence, the correct option is (B).