Tag: compounds of phosphorus- pcl5

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Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

$\mathrm{B}$ottle of $\mathrm{P}\mathrm{C}l _{3}$ is kept stoppered because it :

  1. explodes

  2. gets oxidized

  3. is volatalised

  4. reacts with moisture
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solution:-
$PCl _3+3H _2O\rightarrow H _3\ PO _3+3HCl$


$PCl _3$ reacts rapidly and exothermically with water to form phosphorus acid ,$H _3PO _3$ and $HCl$.

Option D is correct.

Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

The products of the hydrolysis of $\mathrm{P}\mathrm{Cl} _{3}$ are :

  1. $\mathrm{H}\mathrm{Cl},\ \mathrm{H} _{3}\mathrm{P}\mathrm{O} _{4}$
  2. $\mathrm{H}\mathrm{Cl},\ \mathrm{H} _{3}\mathrm{P}\mathrm{O} _{3}$
  3. $\mathrm{Cl} _{2},\ \mathrm{H} _{3}\mathrm{P}\mathrm{O} _{3}$
  4. $\mathrm{H}\mathrm{Cl},\ \mathrm{P}\mathrm{O}\mathrm{Cl} _{3},\ \mathrm{H} _{3}\mathrm{P}\mathrm{O} _{4}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

 Hydrolysis of $PCl _3$ gives:

$2PCl _3+6H _2O\rightarrow 2H _3PO _3+6H+$

$PCl _3+3H _2O\rightarrow H _3PO _3+3H+$

Option B is correct.

Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

The products formed by the complete hydrolysis of $P{Cl} _{3}$ are:

  1. ${H} _{3}{PO} _{3}$ and $HCl$
  2. $PO{Cl} _{3}$ and $HCl$
  3. ${H} _{3}{PO} _{4}$ and $HCl$
  4. ${H} _{4}{P} _{2}{O} _{7}$ and $HCl$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
The products formed by the complete hydrolysis of $PCl _3$ are as follow:
$PC{ l } _{ 3 }+3{ H } _{ 2 }O\rightarrow { H } _{ 3 }P{ O } _{ 3 }+3HCl$

${ H } _{ 3 }P{ O } _{ 3 }$ and $HCl$ are the products formed.
Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

On hydrolysis, $PCI _3$ gives :

  1. $H _3PO _3$
  2. $H _3PO _4$
  3. $POCI _3$
  4. $HPO _3$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
$PCl _{3}$ on hydrolysis gives $HCl$ and $ H _{3}PO _{3}$

$PCl _{3}+ 3H _{2}O\rightarrow H _{3}PO _{3}+3HCl$

Phosphorus trichloride reacts violently with water forming phosphorous acid.

Option (A) is correct .

Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

Choose the correct statement.

  1. White or yellow phosphorus is stored under water

  2. Ignition temperature of red phosphorus is low

  3. Black phosphorus is non crystalline in nature

  4. Phosphorus does not form hydrides
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Due to low ignition temperature of white phosphorus, it undergoes oxidation in presence of air which slowly raises its temperature and after a few moments it catches fire spontaneously. Due to this reason, it is stored under water. Ignition temperature ofred phosphorus is high Black phosphorus is crystalline in nature. Phosphorus forms a number of hydrides

Multiple choice chemistry p- block elements-ii compounds of phosphorus - pcl3 phosphorus halides compounds of phosphorus compounds of phosphorus- pcl5

Is ${PCl} _{3}$ soluble in water?

  1. Not Soluble

  2. May be

  3. Partially soluble

  4. Soluble
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation
like dissolve like. It means polar molecules dissolves in polar molecules and non-polar molecules.Molecules dissolves in non polar molecules $Water$ and $PCl _3$ both are polar molecules because of their shape and electronegative difference between $H$ and $O$ in water and $P$ and $Cl$ in $PCl _3$. Hence $PCl _3$ is solube in water.
$PCl _3$ dissolve in water to form phosphorous acid.
$PCl _3$ $+$ $3H _2O$  $\longrightarrow $   $H _3PO _3$ $+$ $3HCl$