Tag: vedic mathematics

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Questions Related to vedic mathematics

Multiple choice maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

Find square root of $9604$ using Vilokanam method.

  1. $98$
  2. $92$
  3. $88$
  4. $82$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

We have to find the square root of $9604$ using Vilokanam method.

Its unit digit is $4$.
Therefore, the unit digit of the square root will be $2$ or $8$. 
Ignoring the last two digits (unit digit and ten’s digit) we get $96$. 
The greatest number whose square is less than or equal to $96$ is $9$.
Adjusting above obtained two unit digits $2$ or $8$ to the right of $9$, we get two numbers $92$ and $98$. 
The unique number with unit digit $5$ which lies between $92$ and $98$ is $95$. 
And  $(95)^2 = 9025$
Since, $9604>9025$, therefore, the required square root is $98$.
Thus $\sqrt{9604}=98$

Multiple choice maths vedic mathematics square roots using vedic maths square and square roots using vedic mathematics history of mathematics

Find square root of $961$ using Vilokanam method.

  1. $29$
  2. $30$
  3. $31$
  4. $32$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

We have to find the square root of $961$ using Vilokanam method.

Its unit digit is $1$.
Therefore, the unit digit of the square root will be $1$ or $9$. 
Ignoring the last two digits (unit digit and ten’s digit) we get $9$. 
The greatest number whose square is less than or equal to $9$ is $3$.
Adjusting above obtained two unit digits $1$ or $9$ to the right of $2$, we get two numbers $31$ and $39$. 
The unique number with unit digit $5$ which lies between $31$ and $39$ is $35$. 
And  $(35)^2 = 1225$
Since, $961<1225$, therefore, the required square root is $31$.
Thus $\sqrt{961}=31$