Tag: vedic mathematics

Questions Related to vedic mathematics

Square of $112$ by Sutra Urdhva-tiryagbhyam method is :

  1. $21844$

  2. $12544$

  3. $16544$

  4. $17644$


Correct Option: B
Explanation:

To find the square of $112$


$112 \ \times \ 112$

5 steps are there to solve this.

(i)  Multiply the unit digits
 $2 \times 2=4$

(ii) Take the units and tens digit to cross multiply and add the products
$(2\times1)+(1\times2)=2+2=4$

(iii) Take all three digits to cross multiply and add the products
$(2\times1)+(1\times2)+(1\times1)=2+2+1=5$

(iv) Take the hundreds and tens digit to cross multiply and add the products
$(1\times1)+(1\times1)=1+1=2$


(v) Multiply the hundred digits
$1\times1=1$


Write the numbers obtained from step (v) to (i) in order.
i.e., $12544$

This the square of $112$ is $12544$.

Square root of $20736.893$ Sub-sutra Anurupenya method is?

  1. $144.78$

  2. $144.11$

  3. $144.0031$

  4. $154.0021$


Correct Option: C

To find the square of $45$ by Ekadhikena Purvena method the digit $4$ should be multiplied by which number.

  1. By its previous number

  2. By zero

  3. By its next number

  4. By ten


Correct Option: C
Explanation:

In ekadhikena purvena the first digit is multiplied by its next number.

$45^2\Rightarrow $ First 2 digits $=4\times 5$
and last two digits are$=5^2=25\ \Rightarrow 45^2=2025$

Square of $113$ by Upsutra Yavadunam Tavadunam Vargecha Yojayet is :

  1. $34569$

  2. $12769$

  3. $54639$

  4. $34359$


Correct Option: B
Explanation:

To find the square of $113$,


This is closer to $100$ (base of 10). Write it as $100+13$.

From this method, we can write,

$\dfrac{(113+13)}{13^2}$  i.e., $\dfrac{Number+deficiency}{deficiency^2}$

$=\dfrac{126}{169}$

As we are using base $100$. Digit in hundred's place gets carryforwarded and added to $126$

ie., $(126+1)69=12769$

$12769$ is the square of $113$.

The Dvanda of 567 can be calculated as :- D(567)=$(x\times 5\times 7)$$+$$6^2$
What is the value of $x$?

  1. $2$

  2. $3$

  3. $4$

  4. $5$


Correct Option: A
Explanation:

$D(567)=(2\times 5\times 7)+6^2\ \therefore x=2$

Find the square of the number $65$ using Vedic Mathematics.

  1. $4235$

  2. $4335$

  3. $4220$

  4. None of these


Correct Option: D
Explanation:
To find $(65)^{2}$
Let's take $a=6$. So, $a5=10a+5$ 
Now, $a5$ square can be obtained as follows
$a5=a(a+1)|25$ where $a(a+1)$ is the left side of the number and right side will always be $25$ for the numbers ending with $5$.
Right side of $65$ will be $6\times 7=42$
and left side will be $25$.
So, the number is $4225$.
Hence, $65^{2}=4225$. 

Square root of $315$ by Dwandwa Yog method is?

  1. $17.84$

  2. $17.74$

  3. $17.54$

  4. $17.64$


Correct Option: B

State the following statement is true or false
We can find the squares of all the numbers using dwandwa yog method

  1. True

  2. False


Correct Option: A
Explanation:

The Vedic method of finding a square root is called the Vedic Duplex method also known as dvandva yog method. As the name implies, the method involves a concept called the duplex of a number.



Square root of $732108$ by Dwandwa Yog method is?

  1. $256.63$

  2. $896.25$

  3. $745.23$

  4. $855.63$


Correct Option: D

Predict square root of $3136$ using Vilokanam method.

  1. $54$

  2. $56$

  3. $64$

  4. $66$


Correct Option: B
Explanation:

We have to find the square root of $3136$ using Vilokanam method.

Its unit digit is $6$.
Therefore, the unit digit of the square root will be $4$ or $6$. 
Ignoring the last two digits (unit digit and ten’s digit) we get $31$. 
The greatest number whose square is less than or equal to $31$ is $5$.
Adjusting above obtained two unit digits $4$ or $6$ to the right of $5$, we get two numbers $54$ and $56$. 
The unique number with unit digit $5$ which lies between $54$ and $56$ is $55$. 
And  $(55)^2 = 3025$
Since, $3136>3025$, therefore, the required square root is $56$.
Thus $\sqrt{3136}=56$