Tag: option b: engineering physics
Questions Related to option b: engineering physics
A capillary tube of area of cross-section A is dipped in water vertically. The amount of heat evolved as the water rises in the capillary tube up to height h is: (The density of water is $\rho$)
Viscous force is somewhat like friction as it opposes, the motion and is non-conservative but not exactly so, because
A liquid flows between two parallel plates along the x-axis. The difference between the velocity of two layers separated by the distance $dy$ is $dv$. If $A$ is the area of each plate, then Newton's law of viscosity may be written as:
If the shearing stress between the horizontal layers of water in a river is $1.5 mN/ m^{2}$ and $\eta _{water}= 1\times10^{-3}Pa-s$ , The velocity gradient is:
An air bubble of radius $1 mm$ moves up with uniform velocity of $0.109ms^{-1}$ in a liquid column of density $14.7 \times 10^{3} kg/m^{3}$, then coefficient of viscosity will be ($g = 10ms^{-2}$)
Match List I with List II and select the correct answer using the codes given below the lists :
| List I | List II |
|---|---|
| p. Boltzmann constant | 1. $[ML^2T^{-1}]$ |
| q. Coefficient of viscosity | 2. $[ML^{-1}T^{-1}]$ |
| r. Planck constant | 3. $[MLT^{-3}K^{-1}]$ |
| s. Thermal conductivity | 4. $[ML^2T^{-2}K^{-1}]$ |
The space between two large horizontal metal plates 6 cm apart, is filled with
liquid of viscosity 0.8 $N/m^2.$ A thin plate of surface area 0.01 $m^2$ is moved parallel to the length of the plate such that the plate is at a distance of 2 m from one of the plates and 4 cm from the other. If the plate moves with a constant speed of 1 m $s^{-1}$, then
A solid ball of density half that of water falls freely under gravity from a height of 19.6 m and then enters the water. Up to what depth will the ball go? How much time will it take to come again to the water surface. Neglect air resistance and viscosity effects in water. ($
g=9.8 \mathrm{ms}^{-2}
$)
A spherical ball of radius $3\times 10^{-4}\ m$ and density $10^{4}\ kg\ m^{-3}$ falls freely under gravity through a distance $h$ before entering a tank of water. If after entering the water, the velocity of the ball does not change, then the value of $h$ is (Given, $viscosity >of> water=9.8\times 10^{-6}\ Nsm^{-2}$ and $\rho _{water}=10^{3}\ kgm^{-3}$)
Assertion (A): In damped vibrations, amplitude of oscillation decreases
Reason (R): Damped vibrations indicate loss of energy due to air resistance