Tag: maths

Required numbers are $10,15,20,25,......96$
This is an A.P. in which $a=10,d=5$ and $l=95$
${t} _{n}=95$ $\Rightarrow$ $a+(n-1)d=95$
$\Rightarrow$ $10+(n-1)\times 5=95$
$\Rightarrow$ $(n-1)\times 5=85$
$\Rightarrow$ $(n-1)=17$
$\Rightarrow$ $n=18$
$\therefore$ Required Sum $=\cfrac { n }{ 2 } (a+l)=\cfrac { 18 }{ 2 } \times (10+95)=(95\times 105)=945$

$5358\times 51=5358\times (50+1)$
$=5358\times 50+5358\times 1$
$=267900+5358$
$=273258$

1397×1397=13972.

78 * 76 = 5928. Using the Nikhilam formula with a base of 80 (sub-base 8), the calculation is (80-2) * (80-4) = 5928.

132 * 124 = 16368. Using the Urdhva Tiryakbhyam method, you multiply vertically and crosswise to obtain the product.

57 * 68 = 3876. The Urdhva Tiryakbhyam method involves multiplying digits vertically and crosswise.

349 * 986 = 344114. This is calculated using the Urdhva Tiryakbhyam method for 3-digit multiplication.

41 * 41 = 1681. This is a standard square calculation.

12 * 14 = 168. This is a standard multiplication.