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Multiple choice maths money math different discounts successive discounts problems on discounts

The original price of a music CD is Rs. $500$. A shopkeeper offers $10\%$ discount on this music CD and then again offers $20\%$ discount on the new price. How much will you have to pay, finally?

  1. $160$
  2. $260$
  3. $360$
  4. $460$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$\Rightarrow$  The original price of CD is $Rs.500$

$\Rightarrow$  New price of CD after $10\%$ discount = $Rs.500-Rs500\times \dfrac{10}{100}=Rs.500-Rs.50=Rs.450$
$\Rightarrow$  Shopkeeper again offers $20\%$ discount on new price of CD.
$\Rightarrow$  So, final price of CD = $Rs.450-Rs.450\times \dfrac{20}{100}=Rs.450-Rs.90=Rs.360$

Multiple choice maths money math different discounts successive discounts problems on discounts

A trader marks his goods at $30\%$ above the cost price and allows a discount of $10\%$. What is his selling price?

  1. $117$
  2. $120$
  3. $99$
  4. $59.45$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the cost price be Rs. $100$

Then, marked price $=$ Rs. $130$
Discount $=10\%$ of the marked price
$=10\%$ of $130$
$=\dfrac {1013}{100}\times 130$
$=13$
Selling price $=$ Marked price $-$ Discount
$=130-13$
$=117$
Therefore, the selling price for his goods is Rs. $117$.

Multiple choice maths money math different discounts successive discounts problems on discounts

The marked price of a ceiling fan is Rs. $1250$ and the shopkeeper allows a discount of $6\%$ on it. Find the selling price of the fan.

  1. $1175$
  2. $2260$
  3. $1150$
  4. $1460$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Given, marked price $=$ Rs. $1250$ and discount $=6\%$

Discount $=6\%$ of marked price
$=6\%$ of $1250$
$=\dfrac {6}{100}\times 1250$
$=75$
Selling price $=$ Marked price $-$ Discount
$=1250-75$
$=1175$
Hence, the selling price of the fan is Rs. $1175$.

Multiple choice maths money math different discounts successive discounts problems on discounts

The original price $P$ of a certain item is first discounted by $20$ percent and then $5$ percent of the discount price is added for sales tax. If the final price, including the sales tax is $\$71.40$, calculate the original price $P$.

  1. $\$59.50$
  2. $\$81.40$
  3. $\$84.00$
  4. $\$85.00$
  5. $\$86.40$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Given, $P$ is the original price of item and get $20\%$ discount. 

Then discounted price $=$$\dfrac{80}{100}P=\dfrac{4}{5}P$
Then sale  tax $5\%$ on discounted price $=$ $\dfrac{5}{100}\times \dfrac{4}{5}P=\dfrac{1}{25}P$.
Then total cost $=$ $\dfrac{4}{5}P+\dfrac{1}{25}P$
But total cost is $71.40$ ....... (given) 
Therefore, $ \dfrac{4}{5}P+\dfrac{1}{25}P=71.40$
$\Rightarrow 20P+P=1785$
$\Rightarrow 21P=1785$
$\Rightarrow P=85$

Multiple choice maths money math different discounts successive discounts problems on discounts

If there is a discount of $30\%$ on a speaker and Mira gets another discount of $20\%$ through her coupon, calculate the price paid by her to buy the speaker, if the original price is $\$100$.

  1. $ $86.00$
  2. $ $77.60$
  3. $ $56.00$
  4. $ $50.00$
  5. $ $44.00$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

There is a initial 30% discount on a $\$ 100$ speaker. This reduces its cost to $\$ 70$. 

Now there is another $20\%$ discount on it. 
Hence, its final price will be $(1-\dfrac{20}{100})\times 70$
$=(1-\dfrac{1}{5})\times 70$
$=\dfrac{4}{5}\times 70=$ 56$

Multiple choice maths money math different discounts successive discounts problems on discounts

A real estate agent puts a house on the market at a higher-than-expected selling price. If the house is not sold in two weeks, then he drops the price by $5\%$, again if it is still not sold in next two weeks, then he drops the price by another $5\%$. After that, he continues to drop the price by $3\%$ every two weeks until it reaches a cut-off amount decided by the home-owner, or the house sells, whichever comes first. If originally house is listed at $ $200,000$ and owner sets a cut-off amount of $ $166,000$, what is the final selling price given that the house sells after being on the market for $9$ weeks?

  1. $\$162,901.25$
  2. $\$164,737.48$
  3. $\$166,000.00$
  4. $\$169,832.45$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Listed price of house $=200,000$ USD

Week $1$ & $2$ $\Longrightarrow$ Price remains same


Week $3$ & $4$ $\Longrightarrow$ $5\%$ reduction in $200,000$ USD

The new price is $200000 \times \dfrac {95}{100} = 190,000$ USD


Week $5$ & $6$ $\Longrightarrow$ $5\%$ reduction in $190,000$ USD
The new price is $190000 \times \dfrac {95}{100} = 180,500$ USD


Week $7$ & $8$ $\Longrightarrow$ $3\%$ reduction in $180,500$ USD
The new price is $180500 \times \dfrac {97}{100} = 175,085$ USD


Week $9$ $\Longrightarrow$ $3\%$ reduction in $175,085$ USD
The new price is $175,085 \times \dfrac {97}{100} = 169,832.45$ USD

Multiple choice maths money math different discounts successive discounts problems on discounts

Find the difference between a discount of $40\%$ and two successive discounts of $36\%$ and $4\%$ for Rs. $10,000$.

  1. Rs. $0$
  2. Rs. $144$
  3. Rs. $256$
  4. Rs. $400$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
Single equivalent discount of two successive discounts of $36\%$ and $4\%$ is,
$\Rightarrow$   $36+4-\dfrac{36\times 4}{100}$
$\Rightarrow$    $40 - 1.44 = 38.56$
$\Rightarrow$Percentage difference = $40 - 38.56 = 1.44$
$\therefore$  Required Difference = $10,000\times \dfrac{1.44}{100} =Rs.144$
Multiple choice maths money math different discounts successive discounts problems on discounts

The difference between the discounts of $40\%$ on Rs. $5000$ and two successive discounts of $36\%$ and $4\%$ on the same price is :

  1. Rs. $62$
  2. Rs. $72$
  3. Rs. $19.3$
  4. Rs. $20$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Single equivalent discount of two successive discounts of $36\%$ and $4\%\,\,:$

$\Rightarrow$ $36+4-\dfrac{36\times 4}{100}=40-1.44=38.56\%$
Percentage difference $=$ $(40-38.56)\%=1.44\%$
Thus required difference $=$ $5000\times \dfrac{1.44}{100}=$ Rs. $72$