Tag: maths

Questions Related to maths

A shopkeeper marks the price of an article at Rs. 800. Find the selling price, if he allows three successive discounts of 10%, 5% and 3%.

maths money math different discounts successive discounts problems on discounts

  1. Rs. 663.48

  2. Rs. 663.40

  3. Rs 663.28

  4. Rs 663.30

Show answer
Correct Option: A
Explanation:

Marked Price of an article=Rs 800.
Price after 1st discount $=$ Rs $800-\cfrac { 10 }{ 100 } \times 800$
$=$Rs $720$
Price after 2nd discount $=$ Rs $720-\cfrac { 5 }{ 100 } \times 720$
$=$Rs $684$
Price after 3rd discount $=$ Rs $684-\cfrac { 3 }{ 100 } \times 684$
$=$ Rs $663.48$
Selling Price after three successive discounts $=$ Rs$ 663.48$

two successive discounts of 10% and 8% = 

maths money math different discounts successive discounts problems on discounts

  1. 17.2 %

  2. 18.2%

  3. 16.2%

  4. None of these

Show answer
Correct Option: A
Explanation:

Let the original price =Rs.100

Discount=10% and 8%
Price after discount=$\dfrac{90}{100}\times \dfrac{8}{100}\times 100=82.80$
$\therefore Discount=100-82.80=17.2%$

The list price of a watch is Rs. 400. A customer gets two successive discounts, the first being 10%. Calculate, in percentage, the second discount, if the customer pays Rs. 306 for it.

maths money math different discounts successive discounts problems on discounts

  1. $11$%

  2. $13$%

  3. $15$%

  4. $18$%

Show answer
Correct Option: C
Explanation:

Given the Marked price is $ Rs 400 $
After $ 10 $ % discount, the Selling price becomes $ 0.9  \times 400 = Rs   360  $
After further $ x $ % discount, the selling price becomes $ \dfrac { (100-x)}{100} \times 360 $

Given, SP $ = Rs 306 $
$ => \dfrac { (100-x)}{100} \times 360 =  306 $
$ => 100 - x = 85 $
$ => x = 15 $
Hence, 2nd discount is  is $ 15 $ %

The difference between a discount of $40\%$ of Rs. $1000$ and two successive discount of $30\%$ and $10\%$ on the same amount is:

maths money math different discounts successive discounts problems on discounts

  1. $0$

  2. $20$

  3. $30$

  4. $40$

Show answer
Correct Option: C
Explanation:

A discount of $40\%$ on Rs. $1000 = \dfrac{40}{100}\times 1000$ 

                                                     $=$ Rs. $400$ 

Two Successive discounts of $30\%$ and $10\%$ reduces price to $= 1000 \times \dfrac{100-30}{100} \times \dfrac{100-10}{100}$
                                                                                                      $=$ Rs. $630$
$\Rightarrow$ Discount $= 1000-630 = 370$

Difference in discount $= 400-370 = 30$

The marked price of an article is Rs. $500$. It is sold at successive discounts of $20\%$ and $10\%$. The selling price of the article (in Rs.) is

maths money math different discounts successive discounts problems on discounts

  1. $350$

  2. $375$

  3. $360$

  4. $400$

Show answer
Correct Option: C
Explanation:

M.P. $=$ Rs. $500$, $1^{st}$ discount $ = 20\%$
Net price after $1^{st}$ discount $= 80\%$ of Rs. $500=\dfrac {80}{100}\times 500=$ Rs. $400$
$2^{nd}$ discount $= 10\%$
$\therefore$ Final S.P. after $2^{nd}$ discount $=\dfrac {90}{100}\times 400$
$=$ Rs. $360$

A shopkeeper allows a discount of $10\%$ on his goods. For cash payments, he further allows a discount of $20\%$. Find a single discount equivalent of the above offer

maths money math different discounts successive discounts problems on discounts

  1. $25\%$

  2. $28\%$

  3. $32\%$

  4. $35\%$

Show answer
Correct Option: B
Explanation:

Let the M.P. $=$ Rs. $ 100$,
$\therefore$ S.P. $=80\%$ of $90\%$ of Rs. $ 100=$ Rs. $ \left (\dfrac {80}{100}\times \dfrac {90}{100}\times 100\right )=$ Rs. $  72$
$\therefore$ Single discount $=$ Rs. $ 100-$ Rs. $ 72=$ Rs. $ 28$
Single discount rate $=\dfrac {28}{100}\times 100=28\%$.

Find the selling price of an article, if a shopkeeper allows two successive discount of $5\%$ each on the marked price of Rs. $ 80$

maths money math different discounts successive discounts problems on discounts

  1. Rs $61.70$

  2. Rs $67.30$

  3. Rs $72.20$

  4. Rs $77.10$

Show answer
Correct Option: C
Explanation:

Given, M.P$=$ Rs. $80$

Two successive  Discount each $=5\%$

$\therefore $ S.P after first discount$=80-5\%$ of $80$

$\Rightarrow 80-\dfrac{5}{100}\times 80$

$\Rightarrow 80-4=$ Rs. $76$

Selling price after second discount $=76-5\% $ of $  76$

$\Rightarrow 76-\dfrac{5}{100}\times 76$

$\Rightarrow 76-3.80=$ Rs. $72.20$

The marked price of a watch is Rs 800. A customer gets two successive discounts on the marked price, the first being 10%. What is the second discount if the customer pays Rs 612 for it?

maths money math different discounts successive discounts problems on discounts

  1. 14%

  2. 15%

  3. 17%

  4. 18%

Show answer
Correct Option: B
Explanation:

$M.P. =Rs 800$, First discount $=$ 10%
$\therefore$ Net price after the first discount $= 90$% of $Rs 800 = 0.9 \times Rs 800 =Rs 720$
Final price after the second discount $=Rs 612$
$\therefore$ Second discount $=Rs 720 -Rs 612 =Rs 108$
$\Rightarrow$ Second discount rate $=\frac {108}{720}\times 100$% $= 15$%.

A single discount equivalent to successive discounts of $30\%, 20\%$ and $10\%$ is

maths money math different discounts successive discounts problems on discounts

  1. $50\%$

  2. $51\%$

  3. $49.4\%$

  4. $49.6\%$

Show answer
Correct Option: D
Explanation:

Let the M.P. $=$ Rs. $ 100$
Then, S.P. after $1^{st}$ discount of $30\%$
$=100-30\%$ of Rs. $ 100 =100-\dfrac{30}{100}\times 100=$ Rs. $ 70$
S.P. after $2^{nd}$ discount of $20\%$
$\Rightarrow 70-$ $20\%$ of Rs. $ 70 =70-\dfrac{20}{100}\times 70$
$\Rightarrow 70-14=$ Rs. $ 56$
Net S.P. after $3^{rd}$ discount of $10\%$
$=56- 10\%$ of Rs. $ 56=56-\dfrac{10}{100}\times 56$

$\Rightarrow 56-5.60 =$ Rs. $ 50.4$
$\therefore$ Total discount $=$ Rs. $ 100-$ Rs. $ 50.4=$ Rs. $ 49.6$
Discount rate $=\dfrac {49.6}{100}\times 100=49.6\%$

A dealer buys a car listed at Rs. $200000$ at successive discounts of $5$ $\%$ and $10$ $\%$. If he sells the car for Rs. $179550$, then his profit is

maths money math different discounts successive discounts problems on discounts

  1. $10$ $\%$

  2. $9$ $\%$

  3. $5$ $\%$

  4. $4$ $\%$

Show answer
Correct Option: C
Explanation:

CP, of the car $=$ $95\%$ of $90\%$ of Rs. $ 200000$

$\Rightarrow \dfrac{95}{100}\times \dfrac{90}{100}\times 200000$
$\Rightarrow 95\times 90\times 20=Rs 171000$
S.P. of the car $=$ Rs. $ 179550$
$\therefore$ Profit $\%$ $=\left (\dfrac {(179550-171000)}{171000}\times 100\right )$ $\%$
$=\left (\dfrac {8550}{171000}\times 100\right )$% $=$ $5$%