Tag: maths

Questions Related to maths

The equation of plane passing through $(-1,0,-1)$ parallel to $xz$ plane is

  1. $y=-2$

  2. $y=0$

  3. $-x-z=0$

  4. None of the above


Correct Option: B
Explanation:

Given that the plane is parallel to $xz$ plane and the plane passes through $(-1,0,-1)$

Since the plane is parallel to $xz$ plane , the $y$ coordinate should be constant
Given that it passes through point $(-1,0,-1)$ , therefore the plane lies on $xz$ plane
Therefore the equation of plane is $y=0$
The correct options are $B$

The planes $2x-y+4z=5$ and $5x-2.5y+10z=6$ are

  1. Parallel

  2. Perpendicular

  3. Intersect

  4. intersect $x$ axis


Correct Option: A
Explanation:

Planes are $2x-y+4z=5$ 

and $5x-2.5y+10z=6$
Multiply both sides by 2 to the second equation
$\Rightarrow 10x-5y+20=12$
Now divide both sides by $2$
$\Rightarrow 2x-y+4z=\dfrac{12}{5}$

Clearly both planes are parallel 

In a three-dimensional space, the equation $3x - 4y = 0$ represents.

  1. A plane containing $Z-axis$

  2. A plane containing $X-axis$

  3. A plane containing $Y-axis$

  4. Passing through $(0, 0)$


Correct Option: A
Explanation:

If we consider the z-part also, then the equation is $3x-4y+0z=0$

Which means on putting any value of z equation will have no effect as $0\times z=0$
$\therefore$ it will be a plane containing $Z-axis$.($\because$ it will pass through all points z if it satisfy condition for$ (x,y) $)
(D) is not right because its plane and not a line so it will pass through $(0,0,0)$ not $(0,0)$.
Hence, $(A)$


The point $(3, 0, -4)$ lies on the

  1. Y-axis

  2. Z-axis

  3. XY-plane

  4. XZ-plane

  5. YZ-plane


Correct Option: D
Explanation:
$(3, 0, -4)$   $\rightarrow$   Given point
Clearly, $y = 0$ and $ x$ and $z$ have non-zero value.
If the point lies on $x-z$ plane, this condition is possible.
Hence, the answer is $XZ$- plane.

Which of the following is true for a plane?

  1. A locus is called a plane if the line joining any two arbitrary points on the locus is also a part of the locus.

  2. Value of $y$ in a $zx$ plane is non-zero.

  3. Value of $z$ in a $xy$ plane is zero.

  4. None of the above


Correct Option: A,C
Explanation:

Option A and C are correct 

A locus is called a plane if the line joining any two arbitrary points on the locus is also a part of the locus. and also Value of z in a xy plane is zero.

There are three points with position vectors $ -2a+3b+5c, a+2b+3c $ and$ 7a-c$. What is the relation between the three points?

  1. Collinear

  2. Forms a triangle

  3. In different plane

  4. None of the above


Correct Option: A
Explanation:

The relation between the three points are collinear

Thus option A is correct answer 

The coordinates of the point where the line through $(3, -4, -5)$ and $(2, -3, 1)$ crosses the plane passing through three points $(2, 2, 1),(3, 0, 1)$ and $(4, -1, 0)$ is

  1. $(1, 2, 7)$

  2. $(-1, 2, -7)$

  3. $(1, -2, 7)$

  4. None of these


Correct Option: A

_____ condition is not considered for the similarity of triangle.

  1. $SAS$

  2. $SSS$

  3. $AAA$

  4. $ASA$


Correct Option: A
Explanation:

$SAS$ is a congruency condition not a smililarity condition of triangle

So option $A$ is correct.

If  in $\Delta PQR$,M and N are  points on PQ and PR and $PQ=1.28 ,PR=2.56,PM=0.18,PN=0.36$ cm. 
then $MN||QR.$

  1. True

  2. False


Correct Option: A
State true or false:

In quadrilateral $ABCD$, its diagonals $AC$ and $BD$ intersect at point $O$, such that
$\displaystyle \dfrac{OC}{OA}=\dfrac{OD}{OB}=\dfrac{1}{3}$, then
$\triangle OAB \sim \triangle OCD$
  1. True

  2. False


Correct Option: A
Explanation:

In $\triangle$s, $OAB$ and $OCD$
$\dfrac{OC}{OA} = \dfrac{OD}{OB}$ (Given)
$\angle AOB = \angle COD$ (Vertically opposite angles)
Thus, $\triangle OAB \sim \triangle OCD$ (SAS rule)