Tag: maths

Questions Related to maths

If 37% of a number is 990.86. What will be approximately 19% of that number?

  1. 600

  2. 500

  3. 700

  4. 550


Correct Option: B
Explanation:

Let the number is x
then $x\times 37\div 100 = 990.80$
$x = 2678 approx$
$ 2678 \times 19 \div 100 = 508 = 500 approx$

If $p _1\%$ of number $N _1$ is equal to $p _2\%$ of number $N _2$, what percent of $N _1$ is $N _2$?

  1. $\displaystyle\frac{100p _1}{p _2}$

  2. $\displaystyle\frac{100p _2}{p _1}$

  3. $\displaystyle\frac{p _1}{p _2}$

  4. $\displaystyle\frac{p _2}{p _1}$


Correct Option: B
Explanation:

$\displaystyle\frac{p _1}{100}\times N _1=\frac{p _2}{100}\times N _2$

$\displaystyle\frac{N _1}{N _2}=\frac{p _2}{p _1}$, $\displaystyle N=\frac{p _2}{p _1}\times N _2$

Percent of $\displaystyle N _1=\left(\frac{p _2}{p _1}\times100\right)\%$ of $N _2$

Percent of $\displaystyle N _2=\left(\frac{p _2}{p _1}\times100\right)\%$ of $N _1$

Successive Comminssion of $20$%, $10$% and $5$% on an atricle is equivalent to the commission

  1. $31$%

  2. $31.6$%

  3. $32.5$^

  4. $35$%


Correct Option: A
Explanation:

Over all discount$=100\%-(80\%\times 90\%\times 95\%)=100\%-68.4\%=31.6\%$

$1000$ is how many times of $10$

  1. $200$

  2. $100$

  3. $300$

  4. $400$


Correct Option: B
Explanation:

$\dfrac { 1000 }{ 10 } =100$

The value of a machine is Rs. $6,250$. It decreases by $10$% during the first year, $20$% during the second year and $30$% during the third year. What will be the value of the machine after $3$ years?

  1. Rs. $2,650$

  2. Rs. $3,050$

  3. Rs. $3,150$

  4. Rs. $3,510$


Correct Option: C
Explanation:
Value after $1^{st}$ year $=6250-\dfrac {10}{100}\times 6250$
$=5625\ Rs$
Value after $2^{nd}$ year $=5625-\dfrac {20}{100}\times 5625=\dfrac {80}{100}\times 5625$
$=4500\ Rs$
Value after $3^{rd}$ year $=4500-\dfrac {30}{100}\times 4500=\dfrac {70}{100}\times 4500$
$=Rs\ 3150$


$88 \% \text { of } 370 + 24 \% \text { of } 210 - x? = 118$

  1. 256

  2. 258

  3. 268

  4. 358


Correct Option: B
Explanation:

$88\% \ of \ 370+24\% \ of \ 210-x=118$

$\dfrac{88}{100}\times 370 +\dfrac{24}{100} \times 210-x=118$

$\dfrac{3256}{10}+\dfrac{504}{10}-x=118$

$325.6+50.4-118=x$
$x=258$

A spider climbed $62\cfrac{1}{2}$% of the height of the pole in one hour and in the next hour it covered $12\cfrac{1}{2}$% of the remaining height. If pole's height is $192m$, then the distance climbed in second hour is:

  1. $3m$

  2. $5m$

  3. $7m$

  4. $9m$


Correct Option: D

In an examination in which full marks were $500$. $A$ got $25$% more than $C$, $C$ got $20$% less than $D$. If $A$ got $360$ marks. What percentage of full marks was obtained by $D$?

  1. $72$%

  2. $80$%

  3. $50$%

  4. $60$%


Correct Option: A
Explanation:
given,full marks in the examination are $500$
A got $360$ marks  
A got $25\%$ more than $C$.
let the marks of $C$ be $'x'$ then, 
$x+\dfrac{25}{100}\times x=360$ 
$\dfrac{5x}{4}=360$
$x=288$
 so,$C$ got $288$ marks . 
given,$C$ got $20\%$ less than $D$ let the marks of $D$ be $'y'$ then,
 $y-\dfrac{20}{100}\times y=288$
 $\dfrac{4y}{5}=288$
$y=360$
 so,$D$ got $360$ marks percentage of full marks obtained by $D$ $=\dfrac{360}{500}\times 100$
$=72\%$

Tulsiram's salary is $20$% more than that of Kashyap. If tulsiram saves RS. $720$ which is $4$% of his salary, then Kashyap's salary is

  1. Rs. $15,000$

  2. Rs. $12,000$

  3. Rs. $10,000$

  4. RS. $22,000$


Correct Option: A
Explanation:

$Salary\quad of\quad Tulsiram$

$ =Rs\quad \dfrac { 720 }{ 4 } \times 100$

$=Rs\quad 18,000$

$Salary\quad of Kashyap\quad $

$=18000\times \dfrac { 100 }{ 120 } $

$ =Rs.15000$

In two successive years, $80$ and $60$ students of a school appeared at the final examination, of which $60$% and $80$% passed respectively. The average rate of students passed (in percent) is:

  1. $68$%

  2. $68\cfrac{4}{7}$%

  3. $32$%

  4. $36$%


Correct Option: B