Problems on Trains Questions

Multiple choice
  1. 20 m, 36 km/h

  2. 35 m, 54 km/h

  3. 40 m, 72 km/h

  4. 50 m, 90 km/h

  5. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the speed of the train be V km/h.

Length of the train be L m.

Length of the first tunnel = T m 

Length of the second tunnel = t m

The train crosses the first tunnel in 12 seconds, so

t = (L + T)/V

12 = (L + 100)/V

12V - L = 100 --------------------(1) 

Similarly, 8 = (L + 60)/V 

8V - L = 60 -----------------------(2) 

From (1) and (2),

V = 10 m/s = 36 km/h 

Now, putting the value of V in equation (1),

12V - L = 100

12(10) - L = 100

L = 20 m

So, length of the train is 20 m and speed is 36 km/h.

Multiple choice
  1. 170 m

  2. 255 m

  3. 340 m

  4. 85 m

  5. None of these

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the length of the train be L m.

Speed of the train (V) = 96 km/h = 96 * 5/18 = 80/3 m/s

Speed of the man (v) = 6 km/h = 6 * 5/18 = 5/3 m/s

Now, by using this shortcut formula,

t = L/(V + v) 

3 = L/(80/3 + 5/3)

L = 85 m, so length of the train is 85 m.

Multiple choice
  1. 99 km/h, 81 km/h

  2. 55 km/h, 45 km/h

  3. 90 km/h, 80 km/h

  4. 72 km/h, 54 km/h

  5. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Length of the faster train (L) = 140 m

Length of the slower train (l) = 110 m

Speed of the faster train = V km/h 

Speed of the slower train = v km/h 

Now, by using the formula,

t = (L +l)/(V - v) 

50 = (140 + 110)/(V - v) 

V - v = 5 ----------------(1) 

Similarly,

t = (L + l)/(V + v) 

5 = (140 + 110)/(V + v) 

V + v = 50 -----------------(2) 

From (1) and (2),

V = 55/2 = (55/2) * (18/5) = 99 km/h

v = (45/2) * (18/5) = 81 km/h So, the speed of the faster train is 99 km/h and the speed of the slower train is 81 km/h.

Multiple choice
  1. 5.67 s

  2. 7.34 s

  3. 1.67 s

  4. 6 sec

  5. 5.82 sec

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Relative speed of the train and the man=(60+6) =66km/h =66 *5/18 m/s Distance=110m Therefore, Time taken in passing the man =Distance/Speed                                                                                                     =(110*18)/(66*5)
=6 s It is the correct answer.

Multiple choice
  1. 5 m/s

  2. 8 m/s

  3. 12 m/s

  4. Cannot be determined

  5. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Speed of train = 108 km/hr = (108*5/18) = 30 m/sec Let the length of the platform be x meters Then, x + 280 m = 360 m x = (360-280) m = 80 m Then, the speed of man = (80 m)/ (10 s) = 8 m/s

Multiple choice
  1. 10 seconds

  2. 15 seconds

  3. 12 seconds

  4. 20 seconds

  5. 25 seconds

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Speed of the first train = 120/10 = 12 m/sec Speed of the second train =120/15 = 8 m/sec Relative speed = (12 + 8) = 20 m/sec Therefore, the required time = (120 + 120)/20 = 12 sec

Multiple choice
  1. 100 m

  2. 435 m

  3. 150 m

  4. 75 m

  5. 360 m

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the length of each train be x metres.

Then, the total distance covered by the faster train in 54 sec = (x + x) = 2x m

Relative speed = (58 - 48) km/h

                      = 10 km/h                                           = (10 * 5)/18 m/s (since both trains are moving in the same direction)

Hence, time = distance/speed

54 = 2x/(50/18)

54 = (2x * 18)/50

x = (54 * 50)/(18 * 2)

x = 3 * 25 x = 75 m

It is the correct answer.

Multiple choice
  1. 100m

  2. 75m

  3. 120m

  4. 50m

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

When two objects move in the same direction, their relative speed is the difference of their speeds. Here, relative speed = 50 - 32 = 18 kmph = 5 m/s. In 15 seconds, the faster train covers length = relative speed × time = 5 × 15 = 75m. This is the length needed for the faster train to completely pass the observer.