Quantitative Aptitude
Problems on Trains
989 Questions
Problems on Trains Questions
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12 s
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10 s
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5 s
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7 s
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None of these
A
Correct answer
Explanation
The relative speed of the train with respect to the man is 52 - 4 = 48 km/h. Convert this to m/s: 48 * (5/18) = 40/3 m/s. Time = distance / speed = 160 / (40/3) = 160 * 3 / 40 = 12 seconds.
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200 metres
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225 metres
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100 metres
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125 metres
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None of these
D
Correct answer
Explanation
Train speed is 36 kmph = 10 m/s. Man speed is 9 kmph = 2.5 m/s. Relative speed when passing man = 10 + 2.5 = 12.5 m/s. Length of train = 12.5 * 14 = 175 meters. Time to pass bridge = 30s. Total distance = 10 * 30 = 300 meters. Bridge length = 300 - 175 = 125 meters.
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240 metres
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140 metres
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1200 metres
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300 metres
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None of these
B
Correct answer
Explanation
Let train length be L and speed be v. L/v = 8. (L+280)/v = 24. From first, v = L/8. Substitute into second: (L+280)/(L/8) = 24 => 8(L+280)/L = 24 => L+280 = 3L => 2L = 280 => L = 140.
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28 m/s
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36 m/s
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20 m/s
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17.5 m/s
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None of these
A
Correct answer
Explanation
Let speeds be v1, v2. Same direction: (v1-v2) = (180+220)/25 = 400/25 = 16. Opposite: (v1+v2) = (180+220)/10 = 400/10 = 40. Adding: 2v1 = 56, v1 = 28 m/s.
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14.4 sec
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15.5 sec
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18.8 sec
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20.2 sec
A
Correct answer
Explanation
Let length of each train be L. Speed 1 = L/18, Speed 2 = L/12. Relative speed (opposite) = L/18 + L/12 = 5L/36. Time to cross = Total distance / Relative speed = (2L) / (5L/36) = 72/5 = 14.4 seconds.
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200 m
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100 m
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50 m
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240 m
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120 m
B
Correct answer
Explanation
The train speed is 36 km/hr, which is 10 m/s. The length of the train is the distance covered in 10 seconds (passing a boy), so 10 m/s * 10 s = 100 m. The train covers the platform length plus its own length in 20 seconds, so 10 m/s * 20 s = 200 m; subtracting the train length gives 200 - 100 = 100 m.
D
Correct answer
Explanation
Let train speed be V. Relative speeds are (V - 3.6) and (V - 5.4) km/hr. Convert to m/s: (V-3.6)5/18 and (V-5.4)*5/18. Distance = speed * time: L = (V-3.6)(5/18)9.6 and L = (V-5.4)(5/18)*9.8. Equating these: 9.6(V-3.6) = 9.8(V-5.4) => 9.6V - 34.56 = 9.8V - 52.92 => 0.2V = 18.36 => V = 91.8 km/hr.
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130.33 m
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160.50 m
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148.33 m
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180.45 m
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100.50 m
C
Correct answer
Explanation
Train speed = 46 kmph = 12.77 m/s. Man speed = 10 kmph = 2.77 m/s. Relative speed = 10 m/s. Train length = 10 m/s * 12 s = 120 m. Total distance for platform = 12.77 m/s * 21 s = 268.27 m. Platform length = 268.27 - 120 = 148.27 m, which rounds to 148.33 m.
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112 m
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126 m
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135 m
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145 m
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158 m
C
Correct answer
Explanation
Speed of train = 36 km/h = 10 m/s. Speed of man = 9 km/h = 2.5 m/s. Relative speed (same direction) = 10 - 2.5 = 7.5 m/s. Length of train = 7.5 m/s * 18 s = 135 m. Time to cross platform = 27 s, so total distance = 10 m/s * 27 s = 270 m. Length of platform = 270 - 135 = 135 m.
C
Correct answer
Explanation
Speed = 72 km/hr = 72 * (5/18) = 20 m/s. Distance = Speed * Time = 20 * 50 = 1000 m. Platform length = Total distance - Train length = 1000 - 250 = 750 m.
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40 seconds
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30 seconds
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25 seconds
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15 seconds
B
Correct answer
Explanation
Relative speed = 30 - 3 = 27 km/hr = 27 * (5/18) = 7.5 m/s. Time = Distance / Speed = 225 / 7.5 = 30 seconds.
B
Correct answer
Explanation
Relative speed of passenger to train A: Train A speed = 30 m/s. Train B speed = 20 m/s. Passenger speed relative to ground = 20 - 2.5 = 17.5 m/s. Relative speed of A to passenger = 30 - 17.5 = 12.5 m/s. Time = Distance / Speed = 125 / 12.5 = 10 s.
A
Correct answer
Explanation
Total distance = 450 + 650 = 1100 m. Time = 36 s. Speed = 1100 / 36 m/s. Convert to km/hr: (1100 / 36) * (18 / 5) = 1100 / 10 = 110 km/hr.
C
Correct answer
Explanation
Total distance to cover = length of train + length of bridge = 200 + 400 = 600 m. Time = distance / speed = 600 / 20 = 30 seconds.
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10 sec
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12 sec
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14 sec
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16 sec
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18 sec
B
Correct answer
Explanation
Relative speed = 46 + 44 = 90 kmph = 90 * (5/18) = 25 m/s. Total distance to cover = 144 + 156 = 300 m. Time = 300 / 25 = 12 seconds.