Quantitative Aptitude
Time and Work
2,195 Questions
Time and Work Questions
B
Correct answer
Explanation
A's rate is 1/15 work/day. B is 25% more efficient, so B's rate is 1.25 × (1/15) = 1/12 work/day. C is 40% more efficient than B, so C's rate is 1.4 × (1/12) = 7/60 work/day. A and C together for 3 days complete 3 × (1/15 + 7/60) = 33/60 work. Remaining work is 27/60. A and B together have rate 1/15 + 1/12 = 9/60. Time needed is (27/60)/(9/60) = 3 days.
B
Correct answer
Explanation
Ram and Shyam together complete work in 8 days, so their combined rate is 1/8 per day. After 3 days, 3/8 work is done, leaving 5/8. Shyam completes 5/8 in 15 days, so Shyam's rate = (5/8)/15 = 1/24 per day. Ram's rate = Combined rate - Shyam's rate = 1/8 - 1/24 = 3/24 - 1/24 = 2/24 = 1/12 per day. Therefore, Ram alone completes the work in 12 days. Options A (17), C (15), and D (13) are incorrect.
C
Correct answer
Explanation
Samir's 1-day work = 1/10, Puneet's 1-day work = 1/15. Together in 3 days, they complete: 3 × (1/10 + 1/15) = 3 × (1/6) = 1/2 of work. Remaining work = 1/2. Ashok worked for 2 days (total 5 days - 3 days already done) to complete the remaining half. So Ashok's 2-day work = 1/2, meaning Ashok's 1-day work = 1/4. Wages distributed proportionally to work done: Samir gets 5/10 × 4500 = 2250, Puneet gets 5/15 × 4500 = 1500, Ashok gets 2/4 × 4500 = 750.
A
Correct answer
Explanation
A's 1 day work = 1/15, B's = 1/10. In 4 days together: 4(1/15+1/10) = 4(5/30) = 2/3. Remaining = 1/3. A + C do 1/3 in 3 days, so (1/15 + 1/C) × 3 = 1/3, giving 1/C = 2/45. C alone does full work in 22.5 days. 40% of work = 0.4 × 22.5 = 9 days. The key is finding C's rate from the combined work rate.
D
Correct answer
Explanation
Each person can do 1/20 of the work per day. Day 1: 1 person completes 1/20. Day 2: 2 persons complete 2/20. Day 3: 3 persons complete 3/20. Day 4: 4 persons complete 4/20. After 4 days, total done = 10/20 = 1/2. Remaining 1/2 is done by 5 persons at 5/20 per day, taking 2 more days. Total = 6 days.
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5 days
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6 days
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4 days
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7 days
A
Correct answer
Explanation
A's work rate = 1/15 per day. B is 25% more efficient, so B's rate = 1.25 × 1/15 = 1/12 per day. In 4 days, A+B complete 4×(1/15+1/12) = 3/5 of work. Remaining 2/5 is done by C in 8 days, so C's rate = (2/5)/8 = 1/20 per day. Combined rate = 1/15+1/12+1/20 = 1/5, so time = 5 days.
A
Correct answer
Explanation
Let one man's daily work = m and one woman's daily work = w. From given: (2m+7w)×28 = 1 and (6m+16w)×11 = 1. Solving simultaneously gives m = 1/154 and w = 1/308. For 7 men: combined rate = 7×(1/154) = 1/22 per day, so time = 22 days.
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6 days
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4 days
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3 days
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2 days
B
Correct answer
Explanation
A's rate = 1/6 work per day, B's rate = 1/8 work per day. Combined A+B rate = 1/6 + 1/8 = 7/24 per day. In 3 days together they complete 3 × 7/24 = 7/8 work. Remaining work = 1 - 7/8 = 1/8. C completes 1/8 work in 2 days, so C's rate = 1/16 per day. B+C combined rate = 1/8 + 1/16 = 3/16 per day. Time to complete 3/4 work = (3/4) / (3/16) = 4 days.
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5.5 days
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7.5 days
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8.5 days
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9.5 days
B
Correct answer
Explanation
This is an inverse proportion problem: more men means fewer days. Total work = 15 × 10 = 150 man-days. For 20 men: Days = 150 ÷ 20 = 7.5 days. Options A (5.5), C (8.5), and D (9.5) are incorrect calculations.
C
Correct answer
Explanation
Work rates: A = 1/x, B = 1/30, C = 1/45 work per day. B and C together: 1/30 + 1/45 = 5/90 = 1/18 per day. In 6 days, B+C complete 6/18 = 1/3 of work. Remaining 2/3 is done by A in 12 days, so A's rate = (2/3)/12 = 1/18. Since A = 1/x, we have 1/x = 1/18, so x = 18 days.
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12 days
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10 days
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18 days
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15 days
A
Correct answer
Explanation
Let A, B, C be work rates (work per day). A + B = 1/20 and B + C = 1/24. Given A = 2C. Substituting: 2C + B = 1/20 and B + C = 1/24. Subtracting: C = 1/20 - 1/24 = (6-5)/120 = 1/80. So A = 2/80 = 1/40 and B = 1/24 - 1/80 = (10-3)/240 = 7/240. Wait, let me verify: from B + 1/80 = 1/24, B = 1/24 - 1/80 = (10-3)/240 = 7/240. For 40% work: B needs 0.40/(7/240) = 96/7 days. Hmm, let me recheck the calculation. Actually, from the given: A + B = 1/20 and A = 2C, so 2C + B = 1/20. Also B + C = 1/24. From these, C = 1/20 - 1/24 + C... wait. Subtracting: (2C + B) - (B + C) = 1/20 - 1/24, so C = 1/120. Then A = 1/60, and B = 1/24 - 1/120 = 4/120 = 1/30. For 40% work by B alone: 0.40/(1/30) = 12 days.
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54 days
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64 days
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72 days
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60 days
C
Correct answer
Explanation
A is three times as efficient as B, so if B does 1 unit/day, A does 3 units/day. Together they do 4 units/day and finish in 18 days, so total work = 4 × 18 = 72 units. B alone does 1 unit/day, so B needs 72/1 = 72 days to complete the work alone.
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90 days
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80 days
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75 days
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100 days
A
Correct answer
Explanation
A is twice as efficient as C, so if C's rate is c, A's rate is 2c. Let B's rate be b. A + B = 1/18, B + C = 1/30, and A = 2C. Substituting: 2C + B = 1/18 and B + C = 1/30. Subtracting: C = 1/18 - 1/30 = (5-3)/90 = 2/90 = 1/45. So C alone takes 45 days, A takes 45/2 = 22.5 days. B = 1/30 - 1/45 = (3-2)/90 = 1/90, so B alone takes 90 days.
C
Correct answer
Explanation
A's 1 day work = 1/80, B's = 1/96. Together with C, they finish in 32 days, so combined rate = 1/32. C's rate = 1/32 - (1/80 + 1/96) = 1/32 - (12/960 + 10/960) = 1/32 - 22/960 = 30/960 - 22/960 = 8/960 = 1/120. So C alone takes 120 days.
B
Correct answer
Explanation
If A is twice as efficient as B, let B's 1 day work = x, then A's = 2x. Together they do 3x work daily. In 13 days, total work = 39x units. B alone at x units/day would need 39x/x = 39 days.