Samir and Puneet can complete the same work in 10 days and 15 days respectively. The work was assigned for Rs.4500. After working together for 3 days Samir and Puneet involved Ashok. The work was completed in total 5 days. What amount (in Rs.) was paid to Ashok?

Samir's 1-day work = 1/10, Puneet's 1-day work = 1/15. Together in 3 days, they complete: 3 × (1/10 + 1/15) = 3 × (1/6) = 1/2 of work. Remaining work = 1/2. Ashok worked for 2 days (total 5 days - 3 days already done) to complete the remaining half. So Ashok's 2-day work = 1/2, meaning Ashok's 1-day work = 1/4. Wages distributed proportionally to work done: Samir gets 5/10 × 4500 = 2250, Puneet gets 5/15 × 4500 = 1500, Ashok gets 2/4 × 4500 = 750.