Quantitative Aptitude
Time, Speed and Distance
2,165 Questions
Time, Speed and Distance Questions
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9 a.m.
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10 a.m.
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10.30 a.m.
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11 a.m.
B
Correct answer
Explanation
At 8 a.m., train A has traveled 20 km. Remaining distance = 110 - 20 = 90 km. Relative speed = 20 + 25 = 45 kmph. Time to meet = 90 / 45 = 2 hours. 8 a.m. + 2 hours = 10 a.m.
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$45 {km}/{hr}$
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$65 {km}/{hr}$
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$85 {km}/{hr}$
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None of these
A
Correct answer
Explanation
Let speeds be v1 and v2. Case 1 (same direction): 120 = (v1 - v2) * 4 => v1 - v2 = 30. Case 2 (opposite direction): 120 = (v1 + v2) * 2 => v1 + v2 = 60. Adding the equations: 2*v1 = 90 => v1 = 45 km/hr.
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$20$ s
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$24.8$ s
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$28.8$ s
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$30$ s
C
Correct answer
Explanation
Relative speed = 20 + 30 = 50 km/h = 50 * (5/18) m/s = 250/18 m/s. Total distance to cover = 200 + 200 = 400 m. Time = Distance / Speed = 400 / (250/18) = 400 * 18 / 250 = 1.6 * 18 = 28.8 seconds.
A
Correct answer
Explanation
Let boat speed be B and current speed be C. Downstream: B+C = 9/2 = 4.5. Upstream: B-C = 9/6 = 1.5. Adding equations: 2B = 6, so B = 3.
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$12.25$ m/s
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$13.5$ m/s
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$15.75$ m/s
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none
B
Correct answer
Explanation
Using s = d/t, s = 135 / 10 = 13.5 m/s.
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$2$ km
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$4$ km
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$8$ km
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$6$ km
D
Correct answer
Explanation
Let total distance be D. Time = (2/3)D/4 + (1/3)D/5 = 1.4 hours (84 minutes). D/6 + D/15 = 1.4. Multiplying by 30 gives 5D + 2D = 42, so 7D = 42, D = 6 km.
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$90$ km/hr, $40$ km/hr
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$40$ km/hr, $80$ km/hr
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$20$ km/hr, $60$ km/hr
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$50$ km/hr, $12$ km/hr
A
Correct answer
Explanation
Let speeds be u and v. Same direction: (u-v) = 250/5 = 50. Opposite direction: (u+v) = 250 / (25/13) = 250 * 13 / 25 = 130. Adding equations: 2u = 180, u = 90. Then v = 40.
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$80$ km/hr, $100$ km/hr
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$98$ km/hr, $100$ km/hr
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$100$ km/hr, $98$ km/hr
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$100$ km/hr, $80$ km/hr
D
Correct answer
Explanation
Let train speed be x and car speed be y. We have 250/x + 120/y = 4 and 130/x + 240/y = 4.3. Solving this system of equations yields x=100 and y=80.
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$875$ km
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$785$ km
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$758$ km
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$857$ km
A
Correct answer
Explanation
Speeds 75 and 50. Ratio of distances = 75/50 = 3/2. Let distances be 3x and 2x. 3x - 2x = 175 => x = 175. Total distance = 3x + 2x = 5x = 5 * 175 = 875 km.
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$2.2\ km/h$
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$2\ km/h$
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$4\ km/h$
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$4.2\ km/h$
A
Correct answer
Explanation
Downstream speed = 48/20 = 2.4 km/h. Upstream time = 20 + 4 = 24 h. Upstream speed = 48/24 = 2 km/h. Speed of boat = (Downstream + Upstream) / 2 = (2.4 + 2) / 2 = 2.2 km/h.
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$10.5\ \text{ km}$
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$11\ \text{km}$
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$10.9\ \text{km}$
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$15\ \text{km}$
A
Correct answer
Explanation
Let distance be D. Upstream speed = 5-2 = 3 km/hr. Downstream speed = 5+2 = 7 km/hr. D/3 - D/7 = 2. (7D - 3D) / 21 = 2. 4D = 42, so D = 10.5 km.
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55 km/h & 35 km/hr
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50 km/h & 35 km/hr
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70 km/h & 60 km/hr
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35 km/h & 25 km/hr
D
Correct answer
Explanation
Let speeds be x and y. Same direction: 80 / (x-y) = 8 => x-y = 10. Opposite direction: 80 / (x+y) = 4/3 => x+y = 60. Solving: 2x = 70 => x = 35, y = 25.
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$20 km$
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$600 km$
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$660 km$
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$360 km$
B
Correct answer
Explanation
Thief travels for 3 hours at 40 km/hr = 120 km lead. Relative speed = 50 - 40 = 10 km/hr. Time to catch = 120 / 10 = 12 hours. Distance traveled by police = 50 km/hr * 12 hr = 600 km.
D
Correct answer
Explanation
Let distance be D. D/5 - D/6 = 20/60 hours. D/30 = 1/3. D = 10 km.
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Speed of the first train is $40$ km/hr and Speed of the second train is $60$ km/hr
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Speed of the first train is $60$ km/hr and Speed of the second train is $80$ km/hr
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Speed of the first train is $100$ km/hr and Speed of the second train is $80$ km/hr
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Speed of the first train is $70$ km/hr and Speed of the second train is $90$ km/hr
B
Correct answer
Explanation
Let the speeds be v and v+20. In 2 hours, the trains cover a combined distance of 300 - 20 = 280 km. Thus, 2(v + v + 20) = 280, which simplifies to 2v + 20 = 140, so 2v = 120 and v = 60. The speeds are 60 km/hr and 80 km/hr.