Time, Speed and Distance Questions

Multiple choice
  1. $2\dfrac{12}{7}$
  2. $4\dfrac{2}{3}$
  3. $2\dfrac{6}{5}$
  4. $4\dfrac{4}{9}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Boat speed b = 28/3. Let current be c. Downstream speed = b+c, Upstream = b-c. Time taken: Upstream = 3 * Downstream. Distance/(b-c) = 3 * Distance/(b+c) => b+c = 3b-3c => 4c = 2b => c = b/2 = (28/3)/2 = 14/3 = 4 2/3.

Multiple choice
  1. $333.3\ m$$
  2. $166.67\ m$
  3. $427\ m$
  4. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Since they are running in the same direction, their relative speed is the difference of their speeds, which is 3 - 2 = 1 km/hr. In 10 minutes (which is 1/6 of an hour), the distance between them will be 1 km/hr * 1/6 hr = 1/6 km, which is approximately 166.67 meters.

Multiple choice
  1. $10 $ kmph
  2. $12$ kmph
  3. $15$ kmph
  4. $20$ kmph
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

When two people meet and finish the remaining journey in times t1 and t2, the ratio of their speeds is v1/v2 = sqrt(t2/t1). Here t1 = 10/3, t2 = 24/5. v1/v2 = sqrt((24/5) / (10/3)) = sqrt(72/50) = sqrt(36/25) = 6/5. 12/v2 = 6/5, so v2 = 10 km/h.

Multiple choice
  1. $4\ km/hr$
  2. $8\ km/hr$
  3. $12\ km/hr$
  4. $16\ km/hr$
  5. $20\ km/hr$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let speed of B be v. Speed of A is v-4. Time taken by B to reach 60 km and return 12 km (total 72 km) is 72/v. Time taken by A to reach 48 km is 48/(v-4). Equating times: 72/v = 48/(v-4). 72v - 288 = 48v. 24v = 288. v = 12. Speed of A = 12 - 4 = 8 km/hr.

Multiple choice
  1. $2.0$ m/s
  2. $3.0$ m/s
  3. $4.0$ m/s
  4. $4.5$ m/s
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Average speed = Total distance / Total time. Total distance = 600 m. Time up = 300 / 3 = 100 s. Time down = 300 / 6 = 50 s. Total time = 150 s. Average speed = 600 / 150 = 4.0 m/s.

Multiple choice
  1. $1 hr$
  2. $1/2 hr$
  3. $1/4 hr$
  4. $1/8 hr$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Relative speed = 70 - 60 = 10 km/h. Relative deceleration = 20 km/h^2. Distance = 2.5 km. Using s = ut + 1/2at^2: 2.5 = 10t - 1/2(20)t^2. 2.5 = 10t - 10t^2. 10t^2 - 10t + 2.5 = 0. Divide by 2.5: 4t^2 - 4t + 1 = 0. (2t - 1)^2 = 0. t = 0.5 hours.

Multiple choice
  1. $36 km/hr^2$
  2. $18 km/hr^2$
  3. $72 km/hr^2$
  4. $144 km/hr^2$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The first car takes D/2 ÷ 30 + D/2 ÷ 45 = D/36 hours, so D = 72 km. For the second car, 72 = 1/2 × a × 2^2, giving a = 36 km/hr^2.

Multiple choice
  1. $6\ m$
  2. $12\ m$
  3. $18\ m$
  4. $24\ m$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Using v^2 = u^2 + 2as. For the first case: 0 = (30)^2 + 2*a*6, so a = -900/12 = -75. For the second case: v=60, a' = 2a = -150. 0 = (60)^2 + 2*(-150)*s. 0 = 3600 - 300s, s = 12 m.

Multiple choice
  1. $1.5\  F$
  2. $3\  F$
  3. $6\  F$
  4. $9\  F$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Work done to stop the body equals its kinetic energy: F * x = (1/2) * m * v^2. Since F * x is constant, F is proportional to v^2. If speed increases from 1 to 3 (a factor of 3), the force must increase by a factor of 3^2 = 9.

Multiple choice
  1. constant speed

  2. acceleration

  3. retardation

  4. none of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The speeds for the three segments are 1 km/min, 0.66 km/min, and 0.5 km/min respectively. Since the speed is decreasing over time, the car is undergoing retardation.