Time, Speed and Distance Questions

Multiple choice
  1. $\dfrac{18}{5}$
  2. $\dfrac{5}{18}$
  3. $\dfrac{13}{5}$
  4. $\dfrac{5}{13}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

To convert km/hr to m/s, you multiply by 1000 meters/km and divide by 3600 seconds/hr. This simplifies to 1000/3600, which is 5/18.

Multiple choice
  1. $40$ miles
  2. $60$ miles
  3. $80$ miles
  4. $100$ miles
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let x be the distance by train and y be the distance by bus. We have x + y = 100 and (x/30) + (y/40) = 3. Solving the system: 4x + 3y = 360 and 3x + 3y = 300. Subtracting gives x = 60, so y = 40.

Multiple choice
  1. $T\times (V_b\times 2V_t)$
  2. $T\times (V_b\times V_t)$
  3. $2\times T\times (V_b+2V_t)$
  4. $2\times T\times (V_b-2V_t)$
  5. $T\times (V_b-2V_t)$
Reveal answer Fill a bubble to check yourself
B Correct answer
Multiple choice
  1. The speed of the car in the rear is 65 km ${ h }^{ -1 }$
  2. In the side mirror, the car in the rear would appear to approach with a speed of 5 km ${ h }^{ -1 }$ to the driver of the leading car
  3. In the rear view mirror, the speed of the approaching car would appear to decrease as the distance between the cars decrease

  4. In the side mirror, the speed of the approaching car would appear to increase as the distance between the car decrease

Reveal answer Fill a bubble to check yourself
C Correct answer
Multiple choice
  1. $\displaystyle 18\dfrac { 2 }{ 11 } { ms }^{ -1 }$
  2. $\displaystyle 9\dfrac { 2 }{ 11 } { ms }^{ -1 }$
  3. $\displaystyle \dfrac { 100 }{ 11 } { ms }^{ -1 }$
  4. $\displaystyle 17\dfrac { 6 }{ 5 } { ms }^{ -1 }$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The train accelerates from 0 to v over 200m, travels at v for the middle distance, and decelerates from v to 0 over 200m. Using v^2 = 2as, v^2 = 2 * 1 * 200 = 400, so v = 20 m/s. Time for acceleration/deceleration is t = v/a = 20/1 = 20s each. Distance covered during these phases is 200m + 200m = 400m. Remaining distance is 4000m - 400m = 3600m. Time for constant speed is 3600/20 = 180s. Total time = 20 + 180 + 20 = 220s. Average speed = 4000m / 220s = 400/22 = 200/11 = 18 and 2/11 m/s.

Multiple choice
  1. $A$ will win the race
  2. $B$ will win the race
  3. the time taken by $A$ to reach the point $C$ is $165$ seconds
  4. the time taken by $B$ to reach the point $C$ is $150$ seconds
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice
  1. $a\rightarrow f , b\rightarrow g, c\rightarrow e,d\rightarrow h$
  2. $a\rightarrow g, b\rightarrow f, c\rightarrow h,d\rightarrow e$
  3. $a\rightarrow h, b\rightarrow g, c\rightarrow h,d\rightarrow e$
  4. $a\rightarrow e, b\rightarrow f, c\rightarrow h,d\rightarrow g$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

a) Average speed for equal distances is 2V1V2/(V1+V2) (g). b) Average speed for equal times is (V1+V2)/2 (f). c) Total displacement for a full round trip is zero, so average velocity is zero (h). d) For free fall from height h, average velocity is sqrt(gh/2) (e).

Multiple choice
  1. $6400$
  2. $6450$
  3. $6200$
  4. $6000$
Reveal answer Fill a bubble to check yourself
B Correct answer
Multiple choice
  1. $1.5h+20d> 60, h+d\leq 6$
  2. $1.5h+20d > 60, h+d\geq 6$
  3. $1.5h+20d < 0, h+d\geq 360$
  4. $20h+1.5d > 6, h+d\leq 60$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The total distance is 20d + 1.5h, and it must be more than 60 miles. The total time spent driving and hiking cannot exceed 6 hours, so h + d <= 6.