Multiple choice

The correct match is: List - I List - II a) A body covers first half of distance with a speed $V_{1}$ and second half of distance with a speed $V_{2}$ e) Average velocity is $\sqrt\frac{gh}{2}$ b) A body covers first half of the time with a speed $V_{1}$ and second half of the time with a speed $V_{2}$ f) Average speed is $\frac{v_{1}+v_{2}}{2}$ c) A body is projected vertically up from ground with certain velocity.Considering its total motion, g) Average speed is $\frac{2V_{1}V_{2}}{V_{1}+V_{2}}$ d) A body freely is released from a height h h) Average velocity is zero

  1. $a\rightarrow f , b\rightarrow g, c\rightarrow e,d\rightarrow h$
  2. $a\rightarrow g, b\rightarrow f, c\rightarrow h,d\rightarrow e$
  3. $a\rightarrow h, b\rightarrow g, c\rightarrow h,d\rightarrow e$
  4. $a\rightarrow e, b\rightarrow f, c\rightarrow h,d\rightarrow g$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

a) Average speed for equal distances is 2V1V2/(V1+V2) (g). b) Average speed for equal times is (V1+V2)/2 (f). c) Total displacement for a full round trip is zero, so average velocity is zero (h). d) For free fall from height h, average velocity is sqrt(gh/2) (e).

AI explanation

When a body covers the first half of a distance at speed V1 and the second half at V2, the average speed formula is 2 multiplied by V1 multiplied by V2 divided by their sum. When it covers half the time at V1 and the other half at V2, the average speed is the sum of the speeds divided by 2, and for a body projected vertically up, the average velocity over the total motion is zero while a body dropped from height h has an average speed of the square root of gh divided by 2, yielding the correct match as a to g, b to f, c to h, and d to e.

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