Quantitative Aptitude
Time, Speed and Distance
2,165 Questions
Time, Speed and Distance Questions
C
Correct answer
Explanation
Upstream speed = 13/5 = 2.6 km/hr. Downstream speed = 28/5 = 5.6 km/hr. Current velocity = (Downstream - Upstream) / 2 = (5.6 - 2.6) / 2 = 1.5 km/hr.
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$2$ km/hr
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$3$ km/hr
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$4$ km/hr
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$5$ km/hr
C
Correct answer
Explanation
Speed in still water (b) = 6 km/hr. Let current speed be c. Downstream speed = 6+c, Upstream speed = 6-c. Time taken = Distance / Speed. Time against current = 6 / (6-c). Time in still water = 6 / 6 = 1. Given 6/(6-c) = 3 * 1. So 6 = 18 - 3c, 3c = 12, c = 4.
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$5$ km
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$6$ km
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$8$ km
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$9.2$ km
B
Correct answer
Explanation
Let total distance be D. Time = 1 hr 24 min = 1.4 hours. (2/3)D / 4 + (1/3)D / 5 = 1.4. D/6 + D/15 = 1.4. (5D + 2D) / 30 = 1.4 => 7D = 42 => D = 6.
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$6$ hr $40$ min
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$6$ hr
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$6$ hr $20$ min
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$7$ hr
A
Correct answer
Explanation
Driving time = 240 km / 40 km/h = 6 hours. The car rests after 80 km and 160 km (2 rests). Total rest time = 2 * 20 min = 40 min. Total time = 6 hours 40 minutes.
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$50$ kmph
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$40$ kmph
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$36$ kmph
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$30$ kmph
C
Correct answer
Explanation
Let speed of goods train be V. Distance covered by goods train in 10 hours = 10V. Distance covered by express train in 4 hours = 90 * 4 = 360. Since they meet, 10V = 360, so V = 36 kmph.
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$420$ km
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$540$ km
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$600$ km
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$650$ km
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$35$
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$\displaystyle 36\frac{2}{3}$
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$\displaystyle 37\frac{1}{2}$
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$40$
D
Correct answer
Explanation
Let distance be D and speed be S. D/S - D/(S+3) = 40/60 and D/(S-2) - D/S = 40/60. Solving this system yields S = 12 km/hr and D = 40 km.
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$25$ km/hr
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$26.67$ km/hr
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$28.56$ km/hr
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$30$ km/hr
B
Correct answer
Explanation
Average speed = Total distance / Total time. Total distance = 200 + 200 = 400 km. Time 1 = 200/40 = 5 hours. Time 2 = 200/20 = 10 hours. Total time = 15 hours. Average speed = 400 / 15 = 26.67 km/hr.
B
Correct answer
Explanation
Total distance = 39 km. Time = 45 min. 15 min at x, 20 min at 2x, 10 min at x. Distance = (x * 15/60) + (2x * 20/60) + (x * 10/60) = 39. (15x + 40x + 10x) / 60 = 39 => 65x = 39 * 60 = 2340 => x = 2340 / 65 = 36.
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$9.20$ $a.m.$
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$9.25$ $a.m.$
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$9.35$ $a.m.$
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$10.25$ $a.m.$
D
Correct answer
Explanation
Anna travels 180 km in the first 2 hours 15 minutes (80 km/h * 2.25 h). The remaining distance is 170 km, which she covers at 60 km/h in 2 hours 50 minutes. Adding 5 hours 5 minutes to 5:20 a.m. results in 10:25 a.m.
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$1$ hour
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$1$ hr $12$ min
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$1$ hr $15$ min
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$1$ hr $20$ min
B
Correct answer
Explanation
Let the usual speed be v and usual time be t. Distance = vt. New speed = (6/7)v, new time = t + 12. Since distance is constant, vt = (6/7)v(t + 12). Dividing by v, t = (6/7)t + 72/7. (1/7)t = 72/7, so t = 72 minutes, which is 1 hour 12 minutes.
C
Correct answer
Explanation
The relative speed of the two cars moving towards each other is 30 + 40 = 70 km/h. The time taken to cover the 280 km distance is distance / relative speed = 280 / 70 = 4 hours. Starting at 3:00 pm, they will meet 4 hours later, at 7:00 pm.
D
Correct answer
Explanation
Let distance be D. Time difference = 7 min + 5 min = 12 min = 1/5 hour. D/5 - D/6 = 1/5. D/30 = 1/5. D = 6 km.
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$100$ km
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$200$ km
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$300$ km
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$400$ km
B
Correct answer
Explanation
Car A travels for 1 hour alone (9am to 10am) covering 40 km. Remaining distance = 400 - 40 = 360 km. Relative speed = 40 + 50 = 90 km/h. Time to meet = 360 / 90 = 4 hours. Car A travels for 1 + 4 = 5 hours. Distance = 5 * 40 = 200 km.
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$1$ hr
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$3$ hr
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$ \displaystyle \frac{1}{3} $ hr
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$30$ hr
B
Correct answer
Explanation
Time = Distance / Speed. Time = 90 km / 30 km/hr = 3 hours.