Quantitative Aptitude

Time, Speed and Distance

2,165 Questions
All Core formulas and unit conversion 441 Boats and streams effective speed 396 Relative speed, meetings, and overtaking 375 Average speed 362 Early and late arrival 321 Proportional relationships 202 Stoppage time per hour 35 Train and stationary or moving object crossing 17 Races and dead heats 16

Time, Speed and Distance Questions

Multiple choice

There is a road beside a river. Two friends started from a place A, moved to a temple situated at another place B and then returned to A again. One of them moves on a cycle at a speed of 6 km/hr, While the other sails on a boat at a speed of 8 km/hr. If the river flows at the speed of 6 km/hr, which of the two friends will return to place A first?

  1. Cyclist

  2. Sailor

  3. Both come at same time

  4. Any other

  5. None
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the distance between A and B be d. The cyclist travels at a constant speed of 6 km/hr both ways, taking a total time of d/6 + d/6 = d/3 hours. The sailor travels downstream at 8 + 6 = 14 km/hr and upstream at 8 - 6 = 2 km/hr, taking a total time of d/14 + d/2 = 4d/7 hours. Since d/3 is less than 4d/7, the cyclist returns first.

Multiple choice

A car P is moving with a uniform speed of 72 km/h towards another car Q at rest on a straight level road. At a particular instant when the distance between P and Q is 525 m, the car Q started accelerating at 2 m/s2 towards P. Find the distance travelled by Q, when both the cars meet.

  1. 300 m

  2. 225 m

  3. 100 m

  4. 30 m
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Car P speed = 72 km/h = 20 m/s. Let time to meet be t. Distance P travels = 20t. Distance Q travels = 0.5 * 2 * t^2 = t^2. Total distance = 20t + t^2 = 525. t^2 + 20t - 525 = 0. (t + 35)(t - 15) = 0. t = 15 seconds. Distance Q travels = t^2 = 15^2 = 225 m.

Multiple choice

A boy covers a certain distance on a toy train. If the train moved 4 kmph faster, it would take 30 minutes less. If it moved 2 kmph slower, it would take 20 minutes more. The distance is

  1. 40 km

  2. 50 km

  3. 60 km

  4. 80 km
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let distance be D and speed be S. D/S - D/(S+4) = 0.5 and D/(S-2) - D/S = 1/3. Solving this system: D = S(S+4)/8 and D = S(S-2)/6. Equating: 6S(S+4) = 8S(S-2) -> 6S+24 = 8S-16 -> 2S=40 -> S=20. D = 20(24)/8 = 60.

Multiple choice

P is driving a car at a speed of 75 km per hour and it covers a distance of 1425 km. Now, P is sailing a boat and the boat takes the same time as taken by the car for travelling downstream from point A to point B and coming back to point C, which is exactly in the middle of points A and B. If the velocity of stream is 4 km/h and the speed of boat in still water is 14 km/h, then what is the distance between A and B?

  1. 180 km

  2. 185 km

  3. 215 km

  4. 220 km

  5. 245 km
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Car speed = 75 km/h, distance = 1425 km. Time = 1425 / 75 = 19 hours. Boat speed in still water = 14, stream = 4. Downstream speed = 18, upstream speed = 10. Let distance AB = D. Time for downstream A to B = D/18. Time for upstream B to C (D/2) = (D/2) / 10 = D/20. Total time = D/18 + D/20 = 19. (10D + 9D) / 180 = 19 => 19D / 180 = 19 => D = 180 km.

Multiple choice

Wyatt once, after a long time, decided to ride his bicycle. He rode it at a speed of 10 miles per hour. The next day, he planned to visit his friend Aiden's house, which was at a greater distance than that he traveled on the first day; he rode at a speed of 14 miles per hour. He observed that if he had ridden at this speed on the first day, he would have covered 20 miles more. What was the actual distance traveled by him on the first day?

  1. 54 miles

  2. 52 miles

  3. 50 miles

  4. 45 miles

  5. 39 miles
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let d be the distance. Time taken at 10 mph is d/10. At 14 mph, time is d/14. The problem states that if he rode at 14 mph, he would cover 20 miles more in the same time as the first day. So, 14 * (d/10) = d + 20. 1.4d = d + 20, 0.4d = 20, d = 50.

Multiple choice

Asher goes to his tuition academy, 'Guidance Heart,' daily by running. One day, he ran at a speed of 10 miles per hour and reached his academy late by 20 minutes. The next day, he ran at a speed of 15 miles per hour and reached early by 15 minutes. What is the distance that he runs daily between his house and his academy?

  1. 17.5 miles

  2. 18.5 miles

  3. 19 miles

  4. 20 miles

  5. 22.5 miles
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let distance be D. Time 1 = D/10, Time 2 = D/15. Difference in time = 20 min + 15 min = 35 min = 35/60 hours. D/10 - D/15 = 35/60. (3D - 2D)/30 = 35/60. D/30 = 35/60. D = 17.5 miles.

Multiple choice

A person rode one-third of a journey at 60 km/hr, one-third at 50 km/hr and the rest at 40 km/hr. Had the person ridden half of the journey at 60 km/hr and the rest at 40 km/hr, he would have taken 4 minutes longer to complete the journey. What distance did the person ride to?

  1. 180 km

  2. 210 km

  3. 240 km

  4. 300 km
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let total distance be D. Time1 = (D/3)/60 + (D/3)/50 + (D/3)/40 = D/180 + D/150 + D/120 = (10D + 12D + 15D)/1800 = 37D/1800. Time2 = (D/2)/60 + (D/2)/40 = D/120 + D/80 = (2D + 3D)/240 = 5D/240 = D/48. Difference = D/48 - 37D/1800 = 4/60 hours = 1/15. Solving for D gives 240 km.

Multiple choice

Directions : Type in your answer in the input box provided below the question. Rahul covered a certain distance in four hours, covering a part of the distance by car, at a speed of 60 km/hr, and the rest of the distance by bike, at a speed of 45 km/hr. Had he interchanged the two modes of transport, it would have taken him 10 minutes more to cover the entire distance. Find the total distance (in km) covered by him. [quizky-text]

  1. 210

  2. 1

  3. 2 : 5

  4. 5 : 8
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let d1 be car distance, d2 be bike distance. d1/60 + d2/45 = 4. d2/60 + d1/45 = 4 + 10/60 = 25/6. Solving this system: d1+d2 = 210 km.