Train A was moving at a speed of 30 km/hr and covered a certain distance, which is 30 km less than the distance covered by train B in "x" hours. If the speed of train B was 50 km/hr and it took 2 hours less than the time taken by train A, then find the distance covered by another train C, which was moving at a speed of 80 km/hr, in (2x + 5) hours.

Let the time taken by train A be t hours, meaning its distance is 30t. Train B takes t minus 2 hours, so its distance is 50 multiplied by (t minus 2). Equating the distances gives 30t + 30 = 50t minus 100, which solves to t = 6.5. The variable x is given as the time for train B, so x equals 4.5 hours. The distance covered by train C is 80 multiplied by (2x + 5), which is 80 multiplied by 14, yielding 1120 km.

• Thanks
• Wrong explanation