Time, Speed and Distance Questions

Multiple choice
  1. Quantity A is greater.

  2. Quantity B is greater.

  3. The two quantities are equal.

  4. The relationship cannot be determined from the information given.

Reveal answer Fill a bubble to check yourself
D Correct answer
Multiple choice
  1. 22 km/hr

  2. 20 km/hr

  3. 24 km/hr

  4. 30 km/hr

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let boat speed be b and stream speed be s. 100/(b+s) + 30/(b-s) = 6. 75/(b+s) + 75/(b-s) = 8. Let u = 1/(b+s) and v = 1/(b-s). 100u + 30v = 6 and 75u + 75v = 8. Solving gives b = 20, s = 5.

Multiple choice
  1. x2 + 80x - 6000 = 0

  2. x2 + 80x - 4800 = 0

  3. x2 + 240x - 1600 = 0

  4. x2 - 80x + 4800 = 0

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Time for car = 240/x. Time for train = 300/(x+20). Given 240/x - 300/(x+20) = 1. 240(x+20) - 300x = x(x+20). 240x + 4800 - 300x = x^2 + 20x. x^2 + 80x - 4800 = 0.

Multiple choice
  1. 60 km/hr

  2. 120 km/hr

  3. 40 km/hr

  4. 80 km/hr

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The time taken by the car is 240/x hours, and the time taken by the train is 300/(x + 20) hours. We are given that the train's time is 1 hour less than the car's time, so 240/x - 300/(x + 20) = 1. Solving this equation or testing the options gives x = 40 km/hr.

Multiple choice
  1. 750 km

  2. 100 km

  3. 150 km

  4. 200 km

  5. 250 km

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

With an average speed of 17 km/h over 10 hours, the total distance travelled is 170 km. Let t be the time spent in the auto; then the time spent walking is 10 - t. Solving the distance equation 5*(10 - t) + 25*t = 170 gives 20*t = 120, so t = 6 hours, and the distance by auto is 25 * 6 = 150 km.

Multiple choice
  1. 12.3pm

  2. 1.30pm

  3. 1.03pm

  4. 2.32pm

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Train A starts at 5am, covers 62*2 = 124km by 7am. Remaining distance = 800 - 124 = 676km. Relative speed = 62 + 50 = 112 kmph. Time to meet = 676 / 112 = 6.0357 hours. 6 hours 2 minutes approx. 7am + 6h 2m = 1:02pm.

Multiple choice
  1. 80 km/hr

  2. 90 km/hr

  3. 70 km/hr

  4. 96 km/hr

  5. 60 km/hr

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

For two objects meeting and then reaching destinations in t1 and t2 time, the ratio of speeds is v1/v2 = sqrt(t2/t1). 80/v2 = sqrt(25/36) = 5/6. v2 = 80 * 6 / 5 = 96 km/h.

Multiple choice
  1. 210 km

  2. 360 km

  3. 420 km

  4. 720 km

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Total time is 12 hours, stay is 5 hours, so travel time is 7 hours. Let distance be d. Total distance is 2d. Average speed = Total distance / Total running time. 60 = 2d / 7, so 2d = 420, d = 210 km.

Multiple choice
  1. 1 minute 13 seconds

  2. 2 minutes 27 seconds

  3. 2 minutes 49 seconds

  4. 2 minutes 54 seconds

  5. 3 minutes 25 seconds

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The diagonal length is sqrt(120^2 + 119^2) = sqrt(14400 + 14161) = sqrt(28561) = 169 meters. At 1 m/s, it takes 169 seconds, which is 2 minutes and 49 seconds.

Multiple choice
  1. 15 kmph

  2. 20 kmph

  3. 18 kmph

  4. 14 kmph

  5. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The average speed is calculated as Total Distance / Total Time. Let the total distance be 100 km; the times are 40/20 = 2 hours, 50/25 = 2 hours, and 10/10 = 1 hour, totaling 5 hours. Average speed = 100 / 5 = 20 kmph.

Multiple choice
  1. 1.5 kmph

  2. 1.2 kmph

  3. 2.2 kmph

  4. 3.5 kmph

  5. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Distance = 0.5 km. Speed = 1 kmph. Time to station = 0.5 hours = 30 minutes. She walked for 6 minutes (0.1 hours), covering 0.1 km. She is 0.4 km from home. She has 30 - 6 = 24 minutes (0.4 hours) left to return home and reach the station. Total distance to cover = 0.1 (to return) + 0.5 (to station) = 0.6 km. Speed = 0.6 / 0.4 = 1.5 kmph.