Two Cars started at same time, same place and towards same direction. First Car goes at uniform speed of 12 Km/hr. Second Car goes at speed of 4 Km/hr in first hour and increases it speed by 1 Km/hr for every hour. Then what is the distance travelled by car B when the both the Cars meet for the first time?

Assuming Car B is the second car with a variable speed, its distance after t hours is the sum of an arithmetic progression with a first term of 4 and a common difference of 1, giving 4t plus t(t-1)/2. The first car travels at a constant speed of 12 km/hr, so setting their distances equal gives 12t = 4t + t(t-1)/2. Solving this quadratic equation results in t = 17, meaning the second car travels 204 km.

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