Multiple choice

Wyatt once, after a long time, decided to ride his bicycle. He rode it at a speed of 10 miles per hour. The next day, he planned to visit his friend Aiden's house, which was at a greater distance than that he traveled on the first day; he rode at a speed of 14 miles per hour. He observed that if he had ridden at this speed on the first day, he would have covered 20 miles more. What was the actual distance traveled by him on the first day?

  1. 54 miles

  2. 52 miles

  3. 50 miles

  4. 45 miles

  5. 39 miles
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let d be the distance. Time taken at 10 mph is d/10. At 14 mph, time is d/14. The problem states that if he rode at 14 mph, he would cover 20 miles more in the same time as the first day. So, 14 * (d/10) = d + 20. 1.4d = d + 20, 0.4d = 20, d = 50.

AI explanation

Assuming the first day's time equals the second day's planned time, the distances traveled at 10 miles per hour and 14 miles per hour differ by 20 miles over the same duration. Using the formula distance equals speed multiplied by time, we can write the equation 14t minus 10t equals 20. Solving for time gives t equals 5 hours, and multiplying this by the first day's actual speed of 10 miles per hour yields an actual distance of 50 miles.

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