Quantitative Aptitude
Pipes and Cisterns
535 Questions
Pipes and Cisterns Questions
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4 hours
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5 hours
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6 hours
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3 hours
C
Correct answer
Explanation
Pipe P fills 1/12 per hour, Q fills 1/16 per hour. Let P run for t hours, then Q runs for full 8 hours. Work by P + Work by Q = 1 full tank. (t/12) + (8/16) = 1. t/12 + 1/2 = 1. t/12 = 1/2. t = 6 hours. P must be turned off after 6 hours. Option C is correct.
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11 am
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12 pm
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12: 30 pm
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1.00 pm
D
Correct answer
Explanation
The combined rate of all 4 pipes is 1/15 + 1/20 + 1/30 + 1/60 = 1/6 per hour. Work done by 9am: pipe1 works 3 hours (3/15), pipe2 works 2 hours (2/20), pipe3 works 1 hour (1/30), totaling 1/3. Remaining 2/3 work takes 4 hours at combined rate. 9am + 4 hours = 1pm.
A
Correct answer
Explanation
In 1 minute: Tap A fills 1/25, Tap B fills 1/30, Tap C empties 1/15. Net rate = 1/25 + 1/30 - 1/15 = (6+5-10)/150 = 1/150. In 100 minutes: 100 × (1/150) = 2/3 filled. So unfilled = 1 - 2/3 = 1/3. The question asks what part remains UNFILLED, which is 1/3.
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3/2 cm.
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4/9 cm.
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5/9 cm.
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5/8 cm.
D
Correct answer
Explanation
Flow rate = 40 cm² × 10 km/hr = 40 m³/hr. In 0.5 hr, volume = 20 m³. Tank base = 3200 m². Rise = 20/3200 m = 5/8 cm.
C
Correct answer
Explanation
Pipe A fills at 1000/15 = 66.67 L/hr. Pipe B fills at 1000/12 = 83.33 L/hr. B is faster by (83.33-66.67)/66.67 = 16.67/66.67 = 0.25 = 25%. The percent more/less is always calculated relative to the base being compared to, which is A here.
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1.8 minute/मिनट
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1.25 minute/मिनट
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15 minute/मिनट
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17.5 minute/मिनट
C
Correct answer
Explanation
Let the outlet tap empty the full tank in x minutes. Combined rate = 1/20 + 1/30 - 1/x = 1/60. Solving: (3+2)/60 - 1/x = 1/60, so 5/60 - 1/x = 1/60, thus 1/x = 4/60 = 1/15, so x = 15 minutes. The outlet empties in 15 minutes, which is slower than either inlet individually fills.
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16 minutes/मिनट
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15 minutes/मिनट
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20 minutes/मिनट
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30 minutes/मिनट
B
Correct answer
Explanation
First pipe fills at 1/12 tank per minute, second pipe empties at 1/20 tank per minute. When both are open, net rate = 1/12 - 1/20 = 1/30 tank per minute. To fill half the tank: (1/2) / (1/30) = 15 minutes. Option D (30 min) would fill a full tank, not half.
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4' O clock
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5' O clock
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6' O clock
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7' O clock
D
Correct answer
Explanation
Pipe rates: A fills 1/6 per hr, B fills 1/5 per hr, C empties 1/2 per hr. At 1 PM: A opens, at 2 PM: B opens, at 3 PM: C opens. Track cumulative: 1-2 PM: A fills 1/6. 2-3 PM: A+B fill 1/6+1/5 = 11/30. Total by 3 PM = 1/6 + 11/30 = 5/30+11/30 = 16/30 = 8/15. At 3 PM, all three open. Net rate = 1/6+1/5-1/2 = 5/30+6/30-15/30 = -4/30 = -2/15 (emptying). To empty 8/15 at rate 2/15: time = (8/15)/(2/15) = 4 hours. So empty at 3 PM + 4 hrs = 7 PM. Option D correct.
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14 minutes/मिनट
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12 minutes/मिनट
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15 minutes/मिनट
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18 minutes/मिनट
B
Correct answer
Explanation
Let pipe B's time = x minutes. Pipe A is 3 times faster, so it fills 3 tanks in the time B fills 1, meaning A's time = x/3 minutes. Given A takes 32 minutes less than B: x - x/3 = 32, so (2x/3) = 32, giving x = 48 minutes. So B takes 48 minutes, A takes 16 minutes. Together: 1/16 + 1/48 = 4/48 tank per minute. Time to fill = 48/4 = 12 minutes. Option B is correct.
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10 hours
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12 hours
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15 hours
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15(1/2) hours
B
Correct answer
Explanation
Combined rate = 1/x + 1/y - 1/z. Given y = (100/3)% of x = x/3, and z = 2x. Rate = 1/x + 3/x - 1/(2x) = (1 + 3 - 0.5)/x = 3.5/x. If this equals 1/12 (to fill in 12 hours), then x = 42 hours. The answer is 12 hours regardless of x's actual value as long as the relationships hold. This is a standard pipes and cisterns problem with one filling, one filling faster, and one emptying.
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5 hr
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4 hr
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5 hr 24 min
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3 hr
C
Correct answer
Explanation
Pipe A fills 1/10 of tank per hour, Pipe B fills 1/12 per hour. Together they fill 1/10 + 1/12 = 11/60 per hour. In 3 hours, they fill 33/60 = 11/20 of tank. Remaining = 9/20 of tank. Pipe B alone needs (9/20) / (1/12) = 9/20 × 12 = 108/20 = 5.4 hours = 5 hours 24 minutes. Option C is correct.
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1716 sec.
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1728 sec.
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3072 sec.
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3084 sec.
B
Correct answer
Explanation
Flow rate = π × (0.25 cm)² × 1000 cm/min = 62.5π cm³/min. Cone volume = (1/3)π(15 cm)²(24 cm) = 1800π cm³. Time = 1800π / 62.5π = 28.8 min = 1728 sec. The pipe radius is 2.5 mm = 0.25 cm, and water flows at 10 m/min = 1000 cm/min.
C
Correct answer
Explanation
Combined rate = 600/60 = 10 L/min. Fill rates: 600/24 = 25 L/min and 600/40 = 15 L/min. Waste pipe = 30 L/min (draining). Combined: 25 + 15 - 30 = 10 L/min ✓. For 60 minutes: 10 × 60 = 600 L. The cistern capacity is 600 litres.
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$\(\frac{3}{4}\) hours$
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$\(\frac{2}{3}\) hours$
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$1 hours$
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$\(\frac{5}{8}\) hours$
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None of these
D
Correct answer
Explanation
Tank is 2/3 filled, so only 1/3 remains empty. Combined rate of both pipes = 1/3 + 1/5 = 8/15 tank per hour. Time to fill remaining 1/3 = (1/3) ÷ (8/15) = 5/8 hours.
D
Correct answer
Explanation
Let K fill tank in k hours, L fill tank in l hours when used for filling. Time together filling: k*l/(k+l). Time with K filling, L draining: k*l/(l-k). Given: k*l/(l-k) = 2 × k*l/(k+l). Simplifying: 1/(l-k) = 2/(k+l), giving k+l = 2l-2k, so 3k = l, meaning K:L = 1:3. Option D is correct.