Quantitative Aptitude
Mixtures and Alligation
1,816 Questions
Mixtures and Alligation Questions
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$10^oC$
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$12.6^oC$
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$13.1^oC$
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$14.2^oC$
C
Correct answer
Explanation
Using the principle of calorimetry, heat lost by hot liquid equals heat gained by cold liquid. m*sA*(32-28) = m*sB*(28-24). This simplifies to 4*sA = 4*sB, so sA/sB = 1/1.
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$38 K$
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$19^{\circ}C$
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$38^{\circ}C$
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none of the above
C
Correct answer
Explanation
Heat lost = Heat gained. m1*c*(T1-T) = m2*c*(T-T2). 200*(80-T) = 300*(T-10). 16000 - 200T = 300T - 3000. 19000 = 500T. T = 38 degrees Celsius.
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$\displaystyle { 50 }^{ \circ }C$
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$\displaystyle { 24.6 }^{ \circ }C$
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$\displaystyle { 49.3 }^{ \circ }C$
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$\displaystyle { 29.6 }^{ \circ }C$
D
Correct answer
Explanation
Using the principle of calorimetry, heat lost by the hot liquid equals heat gained by the cold liquid. Since the specific heat is the same, it cancels out: 2(100 - T) = 8(T - 12). Solving for T gives 200 - 2T = 8T - 96, so 10T = 296, T = 29.6 degrees Celsius.
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$\displaystyle { 15 }^{ \circ }C$
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$\displaystyle { 7.5 }^{ \circ }C$
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$\displaystyle { 4.2 }^{ \circ }C$
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$\displaystyle { 6.25 }^{ \circ }C$
D
Correct answer
Explanation
Using the principle of calorimetry, the heat gained by liquid A equals the heat lost by liquid B. This gives the equation m_A * c_A * (T_f - T_A) = m_B * c_B * (T_B - T_f). Substituting the given values, we get 400 * 2.4 * (25 - T_A) = 750 * 1.6 * (40 - 25), which simplifies to T_A = 6.25 degrees Celsius.
A
Correct answer
Explanation
Heat lost = Heat gained. m1 * c1 * (T1 - T) = m2 * c2 * (T - T2). m1 * 0.3 * (90 - 60) = m2 * 0.5 * (60 - 15). m1 * 0.3 * 30 = m2 * 0.5 * 45. 9 * m1 = 22.5 * m2. m1/m2 = 22.5 / 9 = 2.5 = 5/2.
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$3 M H_2O_2$
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$0.5 M H_2O_2$
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$25.5 g/L H_2O_2$
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None of these
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$165$ ml water
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$65$ ml water
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$100$ ml solution
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$1000$ ml solution
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6.2 gm
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4.12 gm
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3.09 gm
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7 gm
A
Correct answer
Explanation
The number of molecules 6.02 * 10^22 is 0.1 moles. Each gas (N2, O2, H2) has 0.1 moles. The molar masses are 28, 32, and 2 g/mol respectively. Total mass = 0.1(28 + 32 + 2) = 0.1(62) = 6.2 grams.
B
Correct answer
Explanation
The initial solution was 300 g. After heating, the solution weighed 130 g. The difference in weight (300 - 130 = 170 g) represents the water that evaporated.
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250 litres
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125 litres
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75 litres
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500 litres
B
Correct answer
Explanation
Water gas is 125L H2 and 125L CO. For 2CO + O2 -> 2CO2, 125L CO requires 62.5L O2. For 2H2 + O2 -> 2H2O, 125L H2 requires 62.5L O2. Total O2 = 62.5 + 62.5 = 125L.
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990mL
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1010mL
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100mL
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1000mL
A
Correct answer
Explanation
Using N1V1 = N2V2: 10N * 10mL = 0.1N * V2. V2 = 100 / 0.1 = 1000mL. Water to be added = 1000mL - 10mL = 990mL.
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$88.89\%$
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$20\%$
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$71.43\%$
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$80\%$
A
Correct answer
Explanation
According to Raoult's Law, the mole fraction in the vapor phase y_i is given by y_i = (P_i^o * x_i) / P_total. Given P1^o = 2k, P2^o = k, and molar ratio x1:x2 = 1:2, then x1 = 1/3 and x2 = 2/3. The partial pressures are p1 = 2k * 1/3 = 2k/3 and p2 = k * 2/3 = 2k/3. Since partial pressures are equal, the mole ratio in vapor is 1:1.